All categories

2 years ago

What is a better estimate for mass of a text book 1 gram or 1 kilogram

Mathematics

1 answer:

ale4655 [162]2 years ago

6 0

Answer:

One kilogram.

Step-by-step explanation:

Things that are one gram include a paper clip and a raisin, meaning that one kilogram would make much more sense. Hope this helps! :)

You might be interested in

vampirchik [111]

Wouldn't that be 108

6 0

3 years ago

Read 2 more answers

What is mBD ? <br> A.112 <br> B.168<br> C.126 <br> D.154

defon

its bok guys bbbbbb

7 0

3 years ago

Read 2 more answers

Please hurry

Crazy boy [7]

Reflected across x axis, down 3 units, and to the left 7 units

the last one is your answer

8 0

3 years ago

The drawing below shows the dimensions of skims kite what is the area of Kim's kite

Leno4ka [110]

Answer:

48 square inches

Step-by-step explanation:

Given

See attachment for kite

Required

The area of the kite

The given kite has a triangular shape.

So, the area is:

$Area = 0.5 * base * height$

From the attachment

$base = 12in$

$height = 8in$

So:

$Area = 0.5 * 12in* 8in$

$Area = 48in^2$

4 0

2 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago