Refer to the diagram shown below.
The volume of the container is 10 m³, therefore
x*2x*h = 10
2x²h = 10
h = 5/x² (1)
The base area is 2x² m².
The cost is $10 per m², therefore the cost of the base is
(2x²)*($10) = 20x²
The area of the sides is
2hx + 2(2xh) = 6hx = 6x*(5/x²) = 30/x m²
The cost is $6 per m², therefore the cost of the sides is
(30/x)*($6) = 180/x
The total cost is
C = 20x² + 180/x
The minimum cost is determined by C' = 0.
That is,
40x - 180/x² = 0
x³ = 180/40 = 4.5
x = 1.651
The second derivative of C is
C'' = 40 + 360/x³
C''(1.651) = 120 >0, so x = 1.651 m yields the minimum cost.
The total cost is
C = 20(1.651)² + 180/1.651 = $163.54
Answer: $163.54
Answer:
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
Step-by-step explanation:
pls give branliest if helped you im in 6th grade and i know all this bc im smarter then how smart i should be.
Answer:
C)265
Step-by-step explanation:
To find the median you list all the numbers in order from least to greatest. The number in the middle is the median.
In this case there are two middle number so you have to add them together then devide them by 2.
700, 740, <u>810, 900</u>, 1050, 1120.
810 + 900 = 1,710
1,710/2 = 855.
Your median is 855.
To find the difference you just subtract the two numbers.
1,120-855= 265.