I need help on this one please and thank you
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Answer:
<em>Degrees of freedom for independence in chi-square statistic</em>
<em>ν = ( r-1) (s-1) =6</em>
Step-by-step explanation:
<u><em>Explanation</em></u><u>:-</u>
Given data chi-square test for independence is being used to evaluate the relationship between two variables
<em>Given "A" is classified into 3 categories</em>
<em>Second 'B' is classified into 4 categories</em>
In this chi-square test, we test if two attributes A and B under consideration are independent or not
We will assume that
<em>Null Hypothesis : H₀</em>: The two variables are independent
<em>Degrees of freedom in chi-square test for independence </em>
<em>ν = ( r-1) (s-1)</em>
<em>Given data 'r' = 3 and 's' = 4</em>
<em>Degrees of freedom for independence </em>
<em>ν = ( r-1) (s-1) = ( 3-1) ( 4-1) = 2×3 =6</em>
<em>Test statistic</em>
<em> χ ² = ∑ </em><em></em>
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