2 consecutive odd integers.....x and x + 2.....the product means multiply....the sum means add.
x(x + 2) = 4(x + x + 2) - 1
x^2 + 2x = 4(2x + 2) - 1
x^2 + 2x = 8x + 8 - 1
x^2 + 2x = 8x + 7
x^2 + 2x - 8x - 7 = 0
x^2 - 6x - 7 = 0
(x - 7)(x + 1) = 0
x - 7 = 0 x + 2 = 7 + 2 = 9
x = 7
x + 1 = 0 x + 2 = -1 + 2 = 1
x = -1
there can be 2 answers for this....
(1) 7 and 9
(2) -1 and 1
Answer:
Step-by-step explanation:
- the given expression is : −4≤11−3x
- we use following operations to solve the inequality:
- by adding 4 on both sides, the inequality will become :
-4+4 ≤ 11-3x +4
0 ≤ 15 -3x
- adding 3x on both sides, the inequality will become:
3x ≤ 15
- dividing both the sides of the inequality by 3, the inequality will become:
3x/3 ≤ 15/3
x ≤ 5 ( since, 15/3 = 5)
- therefore the solution for x as an inequality will be x ≤ 5
the answer should be 24 because you can divide it into 2 shapes and solve them separately and add those products
Answer:
C
Step-by-step explanation:
Using the pythagorean theorem, we can determine if these are right triangles or not.
equation: sqrt a^2+b^2=c
this means the square root of the two shortest sides squared must equal to the largest side, (the hypotenuese).
Work for C:
Squareroot of 32^2 + 24^2 = 40cm