I don’t understand what I’m supposed to do. Someone pls help :’/

PLEASE HELP ME!! I WILL MARK THE FIRST CORRECT ANSWER BEAINLIEST!!))

sergey [27]

Answer:

7598.80

Step-by-step explanation:

V=πr^2h

= 3.14 * 11^2 * 20

= 2420π or 7598.80

6 0

2 years ago

Read 2 more answers

F(x) = a(x - h)power of 3 + k please describe what a, h and k do within our function.

Zarrin [17]

F(x) = a(x - h)³ + k

The parent graph is F(x) = x³

k - shifts the parent graph up k-units (or down if it is negative). This is also called a vertical shift.

h - shifts the parent graph to the right h-units (or left if it is negative). This is also called a horizontal shift.

a - stretches the parent graph vertically by a factor of "a"

Additonally, the coordinate (h, k) is the center/vertex of the graph.

6 0

3 years ago

Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).

bija089 [108]

Note: Since you missed to mention the the expression of the function $p(x)$ . After a little research, I was able to find the complete question. So, I am assuming the expression as $p(x)=x^4-9x^2-4x+12$ and will solve the question based on this assumption expression of $p(x)$ , which anyways would solve your query.

Answer:

As

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial $p(x)=x^4-9x^2-4x+12$

As

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say $p(x)$ , $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ , we must have to evaluate $p(x)$ for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$