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avanturin [10]
4 years ago
14

2(z-4z)+6+7z please help me

Mathematics
2 answers:
Annette [7]4 years ago
7 0
Answer is z+6 to this problem
ValentinkaMS [17]4 years ago
3 0
2(z-4z)+6+7z<span><span><span>=−<span>6z</span></span>+6</span>+<span>7z</span></span><span>=<span><span>(<span><span>−<span>6z</span></span>+<span>7z</span></span>)</span>+<span>(6)</span></span></span><span>=<span>z+<span>6</span></span></span>
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1 .Find the decimal expansion of 7/8
saw5 [17]

Answer:

the decimal expansion of 7/8 is

0.875

6 0
3 years ago
ms rodriguez has 24 students in her class room. 10 of the students are boys. Jeff claims that the ratio of boys to girls must be
nignag [31]

Answer:

The answer instead is 10:14.

Step-by-step explanation:

In this case, there are ten boys and fourteen girls in this class. The ration would then be 10:14. Instead, Jeff said 5:12 which isn't correct. He can correct it by using the number of boys given, find the difference of girls in a class of twenty-four students, and then get his answer!

8 0
2 years ago
Chandra had 9 jugs of juice at her party.Eacu jig had 1 gallon of juice in it at the start of the party.
soldi70 [24.7K]

Answer:

could you explain more clearly for me? if Chandra had 9 jugs, each was one gallon, what's the take away? I need to know for example: each member had 2 cups of juice which would sum up to (insert number) how much juice was left?

3 0
3 years ago
Is -22 an irrational number???
evablogger [386]
-22 is not an irrational number     





6 0
3 years ago
Read 2 more answers
Given f''(x) = - 16 sin(4x) and f'(0) = - 4 and f(0) = - 2.<br><br> Findf(1) =
cestrela7 [59]

Answer:

The complete equation is f(x) = \sin 4x -8\cdot x -2. f(1) = -10.756

Step-by-step explanation:

Let be f''(x) = -16\cdot \sin 4x, we need to determine the formula of f(x) by integrating twice:

f'(x) = \int {(-16\cdot \sin 4x)} \, dx

f'(x) = -16\int {\sin 4x} \, dx

We apply the following algebraic substitution in expression above:

u = 4\cdot x and du = 4\,dx

f'(u) = -4\int {\sin u} \, du

f'(u) = 4\cdot \cos u + C_{1}

f'(x) = 4\cdot \cos 4x + C_{1}

We use the same approach to determine f(x):

f(x) = \int {(4\cdot \cos 4x)} \, dx + \int {C_{1}} \, dx

f(u, x) = \int {\cos u} \, du + C_{1}\int \, dx

f(u,x) = \sin u + C_{1}\cdot x + C_{2}

f(x) = \sin 4x + C_{1}\cdot x + C_{2}

If we know that f'(0) = -4 and f(0) = -2, the integration constants are obtained below:

4 + C_{1} = -4

C_{1} = -8

C_{2} = -2

The complete equation is f(x) = \sin 4x -8\cdot x -2. (Angles are measured in radians) Then:

f(1) = \sin 4 - 8- 2

f(1) = -0.756-8-2

f(1) = -10.756

4 0
4 years ago
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