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KIM [24]
2 years ago
15

Based on a sample survey, about

Mathematics
1 answer:
Vesna [10]2 years ago
8 0
Your answer will be B
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How do you do ordered pairs
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 please answer ASAP, also, who ever answers if first and has the best explination and work will get the BRAINLIEST crown, and a
Scrat [10]

Volume of 1/4 gal

= Volume of 2/3 bin


Volume(x gal)

= Volume( 1 bin)


So, (1/4)/(2/3)

= x/1


(1/4)/(2/3)

= x



(1/4)/(3/2)

x = 3/8 (Total balance required to fill the entire bin)




In order to fill the bin, the additional gallons need to be added to the initial 1/4 gallon



Therefore, 3/8 - 1/4 = 1/8 gallons










Hope that helps!!!!



7 0
3 years ago
How can I solve this question
Rus_ich [418]
To find the volume of the prism, you need to know the length, height, and width. 
since the length is 4 blocks wide, you can multiply 4 by the length of a single block. 4*1/2 = 4/2. do this for the height and width
Length 4/2
height 7/2
width 3/2
you would then multiply all of them together.
to multiply fractions, just multiply the numerators together and the numerators together

4/2*7/2*3/2 = 84/8
both 84 and 8 are divisible by 4 so you could simplify the fraction to 21/2
the answer is C
3 0
3 years ago
Find dy/dx by implicit differentiation for ysin(y) = xcos(x)
tatyana61 [14]

Answer:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

Step-by-step explanation:

So we have:

y\sin(y)=x\cos(x)

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[y\sin(y)]

We can use the product rule:

(uv)'=u'v+uv'

So, our derivative is:

=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]

We must implicitly differentiate for y. This gives us:

=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]

For the sin(y), we need to use the chain rule:

u(v(x))'=u'(v(x))\cdot v'(x)

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})

Simplify:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}

And we are done for the right.

Right Side:

We have:

\frac{d}{dx}[x\cos(x)]

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]

Differentiate:

=\cos(x)-x\sin(x)

So, our entire equation is:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

And we're done!

5 0
3 years ago
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