Question

Can someone please help me with this math question

Answer 1

Answer:

C'(4,4)

Step-by-step explanation:

The dilation of quadrilateral ABCD over the origin by a scale factor of 2 has the rule

(x,y)→(2x,2y)

So,

• A(-3,-1)→A'(-6,-2)
• B(-1,1)→B'(-2,2)
• C(2,2)→C'(4,4)
• D(3,-2)→D'(6,-4)

Hence, the coordinates of the image point C' are (4,4) (see attached diagram for details)

Answer 2

Answer:

The coordinates of C' = (4,4)

Step-by-step explanation:

The coordinates of C can be found by looking at the graph,

Coordinates of C = (2,2)

ABCD is dilated by a factor of 2 to get A'B'C'D'.

So, the coordinates of C' will be found by multiplying the coordinates of C by 2.

C' = (2*2,2*2)

C' = (4,4)

So, The coordinates of C' = (4,4)