Can someone please help me with this math question
2 answers:
Answer:
C'(4,4)
Step-by-step explanation:
The dilation of quadrilateral ABCD over the origin by a scale factor of 2 has the rule
(x,y)→(2x,2y)
So,
- A(-3,-1)→A'(-6,-2)
- B(-1,1)→B'(-2,2)
- C(2,2)→C'(4,4)
- D(3,-2)→D'(6,-4)
Hence, the coordinates of the image point C' are (4,4) (see attached diagram for details)
Answer:
The coordinates of C' = (4,4)
Step-by-step explanation:
The coordinates of C can be found by looking at the graph,
Coordinates of C = (2,2)
ABCD is dilated by a factor of 2 to get A'B'C'D'.
So, the coordinates of C' will be found by multiplying the coordinates of C by 2.
C' = (2*2,2*2)
C' = (4,4)
So, The coordinates of C' = (4,4)
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Step-by-step explanation:
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T(K) = T(°C) + 273.15;
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