Answer:
Step-by-step explanation:
1 - f(x) = f (x + 2) = 2^x+2
{ when x = 0, y = 2² = 4 }
so the function { y - intercept at (0, 4) }
2 - m(x) = -f(x) = - 2^x
2^x increases as x increases
So -2^x {decreases as x increases}
3 - g(x) = 2f(x) = 2, 2^x = 2^x+1
{ when x = 0, y = 2^1 = 2 }
So the function { y-intercept at (0, 2)
4 - h(x) = f(x)+ 2 = 2^x + 2
f(x)'s asymptote of y = 0
so {f(x) + 2}'s asymptote of y =2