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max2010maxim [7]
2 years ago
5

The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?

Mathematics
1 answer:
Mnenie [13.5K]2 years ago
5 0

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3.  2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

  • mass = 2g
  • molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

133.34g = 6.023*10^2^3

If we equate this

133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

#SPJ1

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Just question 1, please.
ANTONII [103]

Step-by-step explanation:

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In this equation, there is an exchange rate of 0.125, meaning that for each yuan put in, 0.125 dollars are coming out. The -5 symbolizes that for each transaction, 5 yuan are being lost, which is the fee for exchanging money.

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For (c), our equation is y = 0.125 * x - 5, with the y representing dollars, x representing yuan, 0.125 representing the exchange rate, and -5 representing the fee for exchaning mone

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