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max2010maxim [7]
1 year ago
5

The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?

Mathematics
1 answer:
Mnenie [13.5K]1 year ago
5 0

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3.  2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

  • mass = 2g
  • molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

133.34g = 6.023*10^2^3

If we equate this

133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

#SPJ1

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<h3>Using Formula:</h3>

\\ \red\bigstar {\underline{\boxed{\color{springgreen}{\textsf{ \textbf{ \: Area \: of \: circle= \:  \: π \:  r \: ² \: }}}}}} \\\\

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\\  \sf \implies \:  \:  \cancel{\frac{ \:  \: 4312 \:  \: }{22}  }\:  =  \: \: r \:  ^{2}  \\

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