![\left[\begin{array}{ccc}22&18\end{array}\right]\times\left[\begin{array}{cccc}5&18&32&40\\25&40&38&12\end{array}\right]\\\\=\left[\begin{array}{cccc}22\cdot5+18\cdot25&22\cdot18+18\cdot40&22\cdot32+18\cdot38&22\cdot40+18\cdot12\end{array}\right]\\\\=\left[\begin{array}{cccc}560&1116&1388&1096\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D22%2618%5Cend%7Barray%7D%5Cright%5D%5Ctimes%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D5%2618%2632%2640%5C%5C25%2640%2638%2612%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D22%5Ccdot5%2B18%5Ccdot25%2622%5Ccdot18%2B18%5Ccdot40%2622%5Ccdot32%2B18%5Ccdot38%2622%5Ccdot40%2B18%5Ccdot12%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D560%261116%261388%261096%5Cend%7Barray%7D%5Cright%5D)
second question:
January: 32 · 22 + 38 · 18 = 704 + 684 = 1388
December: 18 · 22 + 40 · 18 = 396 + 720 = 1116
1388 - 1116 = 272
Answer: $272.
A:C
Step-by-step explanation:
Answer:
<u>D) (f o g)(x) = 10x² - 60x + 93</u>
Step-by-step explanation:
f(x) = 10x² + 3
g(x) = x - 3
⇒ (f o g)(x)
⇒ f(x - 3)
⇒ f(x - 3) = 10(x - 3)² + 3
⇒ f(x - 3) = 10(x² - 6x + 9) + 3
⇒ f(x - 3) = 10x² - 60x + 90 + 3
⇒ <u>(f o g)(x) = 10x² - 60x + 93</u>
The two regular hexagons could have different side lengths, so they will not necessarily always be congruent, but they will always be similar.
