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MA_775_DIABLO [31]
3 years ago
8

Describe the mistake that Jude made.

Mathematics
1 answer:
stiks02 [169]3 years ago
4 0
Jude has to simplify the parenthesis first then multiply. She didn't follow PEMDAS
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Jason eats 10 ounces of candy in 5 days. a. How many pounds does he eat per day?
Nadusha1986 [10]
A. He eats 1/8 a pound of candy each day.
B. It would take him a total of 8 days to eat a pound of candy.

A. Since he ate 10 ounces in 5 days, you divide 10 by 5 to find he ate 2 ounces per day. Since there are 16 ounces in a pound that would be your denominator (bottom of fraction) and 2 would be the numerator (top of your fraction). You will get 2/16 which if you simplify (divide by 2) you get 1/8.

B. Knowing that there are 16 ounces per pound and he ate 1/8 pound ( 2/16 pound or 2 ounces) a day, you can either look at the simplified denominator to get the answer, or, divide 16 by 2 to get your answer.

I hope this helps!
8 0
3 years ago
Show me how much to shade
Gnoma [55]
If you're talking about inequality graphs, you shade the area where any point in the shaded area can solve the inequality, if I remember correctly. I can't exactly show you how much to shade.
3 0
3 years ago
Please help me with this homework show me how you get it and the answer
Korvikt [17]
Answer -226.8 cubed
step-by-step-equation
3 0
3 years ago
If A=(0,0) and B=(8,2), what is the length of AB
NeX [460]

Answer:

\boxed{\sf Distance_{AB}= 8.24 \ units }

Step-by-step explanation:

Here two points are given to us and we need to find the distance between the two points . The given points are , <u>A(</u><u>0</u><u>,</u><u>0</u><u>)</u><u> </u>and <u>B(</u><u>8</u><u>,</u><u>2</u><u>)</u> . The distance between the two points can be found out using the<u> </u><u>Distance</u><u> Formula</u><u> </u>, which is ,

<em>Distance Formula:- </em>

\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}

Therefore on substituting the respective values ,we can find the Distance as ,

\sf\longrightarrow Distance = \sqrt{ ( 0 - 8)^2 + (0-2)^2}

<u>Simpl</u><u>i</u><u>fy </u><u>the </u><u>brackets</u><u> </u><u>,</u>

\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}

Square the numbers inside the squareroot ,

\sf\longrightarrow Distance =\sqrt{ 64 + 4}

Add the numbers inside the squareroot ,

\sf\longrightarrow Distance = \sqrt{68}

Find the value of squareroot,

\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}

<u>Hence</u><u> the</u><u> </u><u>distance</u><u> between</u><u> the</u><u> two</u><u> points</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u><u>2</u><u>4</u><u> </u><u>units </u><u>.</u>

3 0
2 years ago
Prove that \displaystyle \frac{\cos \theta}{1 + \sin \theta} = \frac{1 - \sin \theta}{\cos \theta}
Bogdan [553]

Answer:

sin^2(θ)+cos^2(θ)=1

Step-by-step explanation:

We know that the statement above is true because of the Pythagorean identity theorem, which states the aforementioned equation. If you solve the equation for 1 you get the same equation.

To do this first multiply both sides by cos(θ), this gives you (cos^2θ)/1+sinθ = 1-sinθ

Then, multiply both sides by sinθ. This equals cos^θ=1-sin^2θ.

Finally, add sin^2θ to both sides. This equals the final answer of cos^2θ+sin^2θ=1. Which is true.

7 0
2 years ago
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