From the given figure ,
RECA is a quadrilateral
RC divides it into two parts
From the triangles , ∆REC and ∆RAC
RE = RA (Given)
angle CRE = angle CRA (Given)
RC = RC (Common side)
Therefore, ∆REC is Congruent to ∆RAC
∆REC =~ ∆RAC by SAS Property
⇛CE = CA (Congruent parts in a congruent triangles)
Hence , Proved
<em>Additional</em><em> comment</em><em>:</em><em>-</em>
SAS property:-
"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)
<u>also</u><u> </u><u>read</u><u> </u><u>similar</u><u> questions</u><u>:</u> Complete this proof. Given: EC AC, DB AC, ∠A = ∠F Prove: ΔMDF ∼ ΔNCA..
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Consider the proof. Given: Segment AB is parallel to line DE. Prove: AD/DC = BE/EC What is the missing statement in Step 5? A.) AC = BC B.) AC/DC = BC/EC C.) AD...
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Answer:
B
Step-by-step explanation:
I believe the answer is B because if we multiply the top equation by 6, we get 48x + 30y = -42, and if we multiply the bottom equation by -5, we get
35x - 30y = 20. So now, if we add it all together, then the positive 30y and negative 30y cancel out aka it equals 0, and thus the variable y is gone, satisfying the requirement that the problem asks for ("Which of these strategies would eliminate a variable...").
I hope this helped, and if it's correct, I'd appreciate if you marked my answer as Brainliest :)
Answer:
Y=5x
Step-by-step explanation:
The first the options aren’t even whole numbers
Answer:
None of the above.
Step-by-step explanation:
The interval where h is increasing is -1.5 < x < 1.5. Answers a, b, and c do not match.