Answer:
-5,3
Step-by-step explanation:
-5x3=-15
-5+3=-2
Answer:
2
Step-by-step explanation:
A=r²
(19/6)=(285/360)r²
Divide both sides by pi, and they cancel out.
x is the radius, so replace r with x.
19/6=285/360x²
19/6÷285/360=x²
(19/6)·(360/285)=x²
4=x²
√4=x
2=x
The absolute value equation that represents the minimum and maximum normal glucose levels is |x - 84.5| = 14.5
<h3>How to write an
absolute value equation that represents the
minimum and
maximum normal glucose levels?</h3>
The given parameters are:
Minimum = 70 mg/dL
Maximum = 99 mg/dL
Calculate the mean using:
Mean = (Minimum + Maximum)/2
This gives
Mean = (70 + 99)/2
Evaluate
Mean = 84.5
Calculate the range using
Range = Maximum -Minimum
This gives
Range = 99 - 70
Evaluate
Range = 29
The absolute value equation that represents the minimum and maximum normal glucose levels is
|x - Mean| = Range/2
So, we have:
|x - 84.5| = 29/2
Evaluate
|x - 84.5| = 14.5
Hence, the absolute value equation that represents the minimum and maximum normal glucose levels is |x - 84.5| = 14.5
Read more about absolute value equation at
brainly.com/question/17795998
#SPJ1
No its not true and im sorry if this is wrong