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Serga [27]
2 years ago
7

Choosing at least one even number when selecting 2 cards from the bag

SAT
1 answer:
Juli2301 [7.4K]2 years ago
3 0

Using the combination formula, it is found that there is a 0.7778 = 77.78% probability of choosing at least one even number.

<h3>What is the combination formula?</h3>

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by:

C_{n,x} = \frac{n!}{x!(n-x)!}

In this problem, there are 10 numbers numbered from 1 to 10.

The total number of outcomes is given by:

T = C_{10,2} = \frac{10!}{2!8!} = 45

The number of outcomes with only odd numbers is given by:

O = C_{5,2} = \frac{5!}{2!3!} = 10

Hence 45 - 10 = 35 outcomes have at least one even number, so the probability is:

p = 35/45 = 0.7778.

More can be learned about the combination formula at brainly.com/question/25821700

#SPJ1

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