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olchik [2.2K]
2 years ago
13

Which of the following can be represented by a single binary digit?

SAT
1 answer:
algol [13]2 years ago
4 0

Answer:

A single binary digit can only represent True (1) or False (0) in boolean logic. However, multiple binary digits can be used to represent large numbers and perform complex functions. In fact, any integer can be represented in binary. ... A byte contains eight bits, which means it can have 256 (28) different values.

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Note that with |x|, the value x will always be positive when simplified. This means that:

B) |-3.5|, |4.2|, |-9| is your answer, because it becomes, 3.5, 4.2, 9

hope this helps

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3 years ago
How often are the modern winter olympic games held
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The Winter Olympics are held every 4 years.
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Newton’s law of cooling states that for a cooling substance with initial temperature t0, the temperature t(t) after t minutes ca
antoniya [11.8K]

The cooling rate of the substance is approximately 0.0732.

According to the statement, the Newton's law of cooling is defined by the following formula:

T(t) = T_{s} + (T_{o}-T_{s})\cdot e^{-k\cdot t} (1)

Where:

  • T_{s} - Final temperature, in degrees Celsius.
  • T_{o} - Initial temperature, in degrees Celsius.
  • t - Time, in minutes.
  • k - Cooling rate, in \frac{1}{min}.
  • T(t) - Current temperature, in degrees Celsius.

Please notice that substance reaches thermal equilibrium when T(t) = T_{s}, that is when temperature of the substance is equal to the temperature of surrounding air.

If we know that T_{o} = 80\,^{\circ}C, t = 15\,min, T_{s} = 50\,^{\circ}C and T(15) = 60\,^{\circ}C, then the cooling rate of the substance is:

60 = 50 + (80 - 50)\cdot e^{-15\cdot k}

\frac{60-50}{80-50}= e^{-15\cdot k}

\frac{1}{3} = e^{-15\cdot k}

k = -\frac{1}{15}\cdot \ln \frac{1}{3}

k \approx 0.0732

The cooling rate of the substance is approximately 0.0732.

To learn more on Newton's law of cooling, we kindly invite to check this verified question: brainly.com/question/13748261

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Explanation:

Took the test !!!

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I don’t think I can help you with this but I hope you get the answer, have a nice day!
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