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kupik [55]
2 years ago
11

Which equation represents a circle that contains the point (–2, 8) and has a center at (4, 0)? distance formula: startroot (x 2

minus x 1) squared (y 2 minus y 1) squared endroot (x – 4)2 y2 = 100 (x – 4)2 y2 = 10 x2 (y – 4)² = 10 x2 (y – 4)² = 100
Mathematics
1 answer:
Rina8888 [55]2 years ago
4 0

The equation of a circle that contains the point (–2, 8) and has a center at (4, 0) is (x - 4)² + y² = 10²

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The circle contains the point (–2, 8) and has a center at (4, 0), hence:

radius=\sqrt{(0-8)^2+(4-(-2))^2}=10\ units

The equation is:

(x - 4)² + (y - 0)² = 10²

(x - 4)² + y² = 10²

The equation of a circle that contains the point (–2, 8) and has a center at (4, 0) is (x - 4)² + y² = 10²

Find out more on equation at: brainly.com/question/2972832

#SPJ4

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