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Alik [6]
2 years ago
9

6, 2, 8, 4, 9 How would the median change if the 6 was replaced by a 3?

Mathematics
1 answer:
xxMikexx [17]2 years ago
7 0

Answer:

4

Step-by-step explanation:

first you put them all in smalet to bigest so it would be 2, 4, 6, 8, 9 but if them 6 was 3 it would be 2, 3, 4, 8, 9

median is the middle numder

Hope This Helped

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F(x) = 2x2 + 12x + 1<br> Determine the vertex
Gnom [1K]

Answer:

Step-by-step explanation:

The vertex would be the highest/lowest point so lets factor this first

when we factor we get

2(x^2+6x+8)

2(x+4) (x+2)

Using zero product property we find the 2 x values and x intercepts are

-4 and -2

the middle point of these points is -3

Substitute -3 for x and solve

2(-3+4) (-3+2)

2 * 1 *  -1

2*-1

-2

(-3,-2) is the vertex

5 0
3 years ago
-6x - 2x = 40. Calculate and show work
xxMikexx [17]
-6x-2x= 40
-8x=40
X= 40/-8
X= -5
3 0
3 years ago
Read 2 more answers
Find the zeros of the function.<br><br> f(x) = 9x2 + 6x - 8
jeyben [28]
Just set it equal to zero and solve using the quadratic equation.
7 0
3 years ago
Read 2 more answers
What is the answer to -4x = 12
coldgirl [10]

Steps to solve:

-4x = 12

~Divide -4 to both sides

x = -3

Best of Luck!

3 0
3 years ago
Read 2 more answers
Find the arc length of the partial circle. <br>length is 1.<br>**See attached photo**<br>​
KatRina [158]

Arc length of the quarter circle is 1.57 units.

Solution:

Radius of the quarter circle = 1

Center angle (θ) = 90°

To find the arc length of the quarter circle:

$\text{Arc length}=2 \pi r\left(\frac{\theta}{360^\circ}\right)

                 $=2 \times 3.14  \times 1\left(\frac{90^\circ}{360^\circ}\right)

                $=2 \times 3.14  \times 1\left(\frac{1}{4}\right)

Arc length = 1.57 units

Arc length of the quarter circle is 1.57 units.

5 0
4 years ago
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