the coordinates of the points of intersection of the graph of y=13−x with the axes
Given equation is y=13-x
x axis is x=0
y axis is y=0
Plug in the value of x =0 and find out y
y = 13 - x
y = 13 - 0 = 13
Plug in the value of y=0 and find out x
0 = 13 - x
x= 13
So coordinate axis
x= (13,0)
y= (0,13)
Base of the triangle is x=13
Height of the triangle is y= 13
Area of the triangle = 
=
= 84.5
Area of the triangle = 84.5
Answer:
3+6×(5+4÷2)-7
Step-by-step explanation:
To solve the expression use order of operations.
Right now the expression solves to:
3+6×5+4÷2-7 6* 5 = 30
3 + 30 + 4÷2-7 4 ÷ 2 = 2
3 + 30 + 2 - 7 Add and subtract left to right.
33 + 2 - 7
35 - 7
28
To make it solve to 38, add parenthesis:
3+6×(5+4÷2)-7 (5+4÷2) = 7
3+6×(7)-7 6*7 = 42
3 + 42 - 7 Add and subtract from left to right
45 - 7
38
Answer:

Step-by-step explanation:
You would substitute "2x" for every "x" in the function in the same way you would substitute any other number.
So if f(x)=Sqrt[7x²-3x], then: f(2x)=Sqrt[7(2x)²-3(2x)]
=Sqrt[7(4x²)-3(2x)]
=Sqrt[28x²-6x]