Answer:
C: Point R
Step-by-step explanation:
Here the "centroid" corresponds to the point where the figure (the triangle) would balance. That's right in the middle, at Point R. C is the correct answer.
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3 ( x ) + 55 = 85
Answer To Solving Y:
Let's solve your equation step-by-step.
3x + 55 = 85
Step 1: Subtract 55 from both sides.
3x + 55 − 55 = 85 − 55
3x = 30
Step 2: Divide both sides by 3.
3x / 3 = 30 / 3
x = 10
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Answer To The Angle:
( 3 ) ( 10 ) + 55 = 85
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2 ( y ) - 5 = 95
Answer:
Let's solve your equation step-by-step.
2y − 5 = 95
Step 1: Add 5 to both sides.
2y − 5 + 5 = 95 + 5
2y = 100
Step 2: Divide both sides by 2.
2y / 2 = 100 / 2
y = 50
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Answer To The Angle:
( 2 ) ( 50 ) − 5 = 95
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Please don't come at me if I am wrong.....:\
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But, the anwer should be 180 degrees
Answer:
B
Step-by-step explanation:
because it says between 4 and 8 and doesn't have a negative so its positive
the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.
from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.
the standing up sides are simply rectangles of 8x3.
if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.
![\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D5%5C%5C%20p%3D24%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%285%29%2824%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bjust%20for%20one%20octagon%7D%7D%7BA%3D60%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwo%20octagon%27s%20area%7D%7D%7B2%2860%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Beight%20rectangle%27s%20area%7D%7D%7B8%283%5Ccdot%208%29%7D%5Cimplies%20120%2B192%5Cimplies%20312)
