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Zepler [3.9K]
4 years ago
13

Center(-3,-4) radius=10 plz help

Mathematics
1 answer:
vovikov84 [41]4 years ago
7 0
Y+4=10(x+3)
Y+4=10x+30
Y=10x+26
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53​% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the
faltersainse [42]

Answer:

a

   P(X = 5) = 0.2423

b

    P( X \ge  6 )=  0.4516

c

   P( X <  4 )=  0.12694

Step-by-step explanation:

From the question we are told that

   The population proportion is   p = 0.53

    The sample size is  n = 10

Generally the distribution of the confidence of US adults in newspapers follows a binomial distribution  

i.e  

         X  \~ \ \ \  B(n , p)

and the probability distribution function for binomial  distribution is  

      P(X = x) =  ^{n}C_x *  p^x *  (1- p)^{n-x}

Here C stands for combination hence we are going to be making use of the combination function in our calculators        

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is exactly​ five is mathematically represented as

     P(X = 5) =  ^{10}C_5 *  0.53^5 *  (1- 0.53)^{10-5}

=>  P(X = 5) =  252 * 0.04182 *  0.023

=>  P(X = 5) = 0.2423

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is  at least​ six is mathematically represented as

  P( X \ge  6 )=  P( X  = 6) +  P( X  = 7) +  P( X  = 8) +  P( X  = 9) +  P( X  = 10)

=> P( X \ge  6 )=  [^{10}C_6 *  [0.53]^6 *  (1- 0.53)^{10-6}] +  [^{10}C_7 *  [0.53]^7 *  (1- 0.53)^{10-7}] +  [^{10}C_8 *  [0.53]^8 *  (1- 0.53)^{10-8}] +  [^{10}C_9 *  [0.53]^9 *  (1- 0.53)^{10-9}] + [^{10}C_{10} *  [0.53]^{10} *  (1- 0.53)^{10-10}]

=> P( X \ge  6 )=  [0.227] +  [0.1464] +  [0.0619] +  [0.0155] + [0.00082]

=> P( X \ge  6 )=  0.4516

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is  less than four is mathematically represented as

    P( X <  4 )=  P( X  = 3) +  P( X  = 2) +  P( X  = 1) +  P( X  = 0)

=>  P( X <  4 )=  [^{10}C_3 *  0.53^3 *  (1- 0.53)^{10-3}] +  [^{10}C_2 *  0.53^2 *  (1- 0.53)^{10-2}] +  [^{10}C_1 *  0.53^1 *  (1- 0.53)^{10-1}] +  [^{10}C_0 *  0.53^0 *  (1- 0.53)^{10-0}]

=>  P( X <  4 )=  0.09051  +  0.03 +  0.0059 +  0.000526

=>  P( X <  4 )=  0.12694

5 0
3 years ago
Did I finally do this correctly?
ArbitrLikvidat [17]

Answer: Yea, Good job :)

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP ME!!!!
Contact [7]
The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)


find slope

slope between (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(-3,2) and (2,1)
slope=(1-2)/(2-(-3))=(-1)/(2+5)=-1/5


pikc a point
if we pick (-3,2)
(x1,y1)
x1=-3
y1=2

y-2=-1/5(x-(-3))
y-2=-1/5(x+3)
that is D
5 0
3 years ago
Solve x2=22. Use a radical sign in each answer<br><br> x=? and x=?
Aleksandr-060686 [28]

Answer:

x=sqrt{22}

Step-by-step explanation:

4 0
4 years ago
On a coordinate plane, a curved line labeled f of x with a minimum value of (1.9, negative 5.7) and a maximum value of (0, 2), c
77julia77 [94]

The graphed function, F(x), has a value greater than 0 over the intervals (-0.7, 0.76) and (0.76,  ∞) . F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞) is the correct statement [Fourth choice].

About a Graphed Function

The function graph of an object F stands for the set of all points in the plane that are (x, f(x)). The graph of f is also known as the graph of y = f. (x). The graph of an equation is thus a specific example of the graph of a function. A graphed function is a function that has been drawn out on a graph.

It is evident from the attached graph that the supplied function exceeds 0 for the following range:

-0.7 < F(x) < 0.76

And, 0.76 < F(x) < ∞

As a result, the intervals for which the given graphed function, F(x) is greater than 0 are as follows,

(-0.7, 0.76) and (0.76, ∞)

Learn more about a graphed function here:

brainly.com/question/27757761

#SPJ1

3 0
2 years ago
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