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2 years ago

313,307,301 find the 42nd term

Mathematics

1 answer:

KatRina [158]2 years ago

5 0

Answer:

-252

Step-by-step explanation:

assuming that 313, 307, and 301 are the first 3 terms..

By these three numbers we can conclude that the rule is -6

(313 - x = 307, 313 - 307 = 6.. x = 6. To check this we do the same thing but with 307 and 301. 307 - x = 301, 307 - 301 = 6, 6 = x)

We find the 42nd term by multiplying our rule by the term number (42)

-6(42) = -252

Remember that a negative times a positive is a negative, but a negative times a negative is positive.

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Write an expression for "the quotient of 9 and c."

frez [133]

Quotient is when something is divided by something. therefore, an equation could be 9/c

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3 years ago

What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago

Find the function !!! 10 points - Help needed!

Arte-miy333 [17]

<h2>Hello!</h2>

The answer is:

The first option,

$f^{-1}(x)=\frac{x-2}{4}$

To find the inverse of a function, we need to rewrite the variable "x" with "y" and the variable "y" with "x", and then, isolate "y".

We are given the function:

$f(x)=4x+2$

Write "f(x)" is equal to write "y", so:

$y=4x+2$

Now, finding the inverse, we have:

$y=4x+2\\x=4y+2\\x-2=4y\\y=\frac{x-2}{4}$

Hence, we have that the answer is the first option,

$f^{-1}(x)=\frac{x-2}{4}$

Have a nice day!

4 0

3 years ago

Read 2 more answers

A rectangle and a square have the same area. The length of the rectangle is seventy feet more than two times its width. The leng

Zanzabum

Using the side of the square find the area:

Area = 30^2 = 900 square feet.

The rectangles area is the same, 900 square feet.

Let the width = X

The length would be 2X + 70

Area = length x width

X * 2x+ 70 = 900

This expands to 2x^2 * 70x = 900

Use the quadratic formula to solve for x:

-70 +/- sqrt(70^2-4*2(-900))/2*2

X = 10

Width = x = 10 feet

Length = 2x + 70 = 90 feet

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2 years ago

Angle A and Angle B are supplementary. If angle A is half the measure of angle B find the measure of each angle

Allushta [10]

Answer:

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Step-by-step explanation:

divide them into three parts- two parts+one half

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3 years ago