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Marat540 [252]
3 years ago
15

A rectangle and a square have the same area. The length of the rectangle is seventy feet more than two times its width. The leng

th of a side of the square is thirty feet. What equation would help you solve for the dimensions of the rectangle? What are the dimensions of the rectangle?
Mathematics
1 answer:
Zanzabum3 years ago
8 0

Using the side of the square find the area:

Area = 30^2 = 900 square feet.

The rectangles area is the same, 900 square feet.

Let the width = X

The length would be 2X + 70

Area = length x width

X * 2x+ 70 = 900

This expands to 2x^2 * 70x = 900

Use the quadratic formula to solve for x:

-70 +/- sqrt(70^2-4*2(-900))/2*2

X = 10

Width = x = 10 feet

Length = 2x + 70 = 90 feet

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Answer:

implifying

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Reorder the terms:

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fx = -3 + 4l + lx

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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We know this because, if we reorganize the equation into the standard form  y = mx + b, we get y = -(x²) + 1. This means that for any value we substitute for x, y will always be negative. The answer is B.

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We have the equation y = (-16t - 2) (t - 1)

We set the equation equal to zero like this:

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Now we just solve for t in both equations:

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Answer:

Step-by-step explanation:

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