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3 years ago

Which is an equation of the line that is perpendicular to 3x+y=-5 and passes through the point (3, -7)?

Mathematics

2 answers:

nataly862011 [7]3 years ago

7 0

Answer:

y+7=1/3(x-3) in point slope

y=1/3x-8 in slope intercept form

Step-by-step explanation:

First put 3x+y=5 in slope-intercept form (y=mx+b)

y=-3x+5

Give that the slope is -3 the perpendicular slope would be 1/3

now using the points (3.-7)

y+7=1/3(x-3) in point slope

y=1/3x-8 in slope intercept form

laiz [17]3 years ago

5 0

Put it in Slope - Intercept Form:

3x + y = -5

-3x -3x

y = -3x - 5

Now plug in the ordered pair that is given:

(3, -7)

y = -3x - 5

-7 = -3(3) - 5

-7 = -9 - 5

-7 = -14

NO, it's false....

Hi, really really sorry if I am incorrect...

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Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

Mr.Silva needs to order pizza for 30 students.Each student should get 1/4 of a pizza.How many pizzas should Mr Silva order?How m

zimovet [89]

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2 years ago

Read 2 more answers

For 33 hrs of work you are paid 252.45 how much would you receive for 36 hours

poizon [28]

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3 years ago

In a newspaper poll concerning violence on television, 589 people were asked, "What is your opinion of the amount of violence on

abruzzese [7]

Answer:

(a) $P(Y'|M)\approx 0.3297$

(b) $P(Y|M')\approx 0.8323$

Step-by-step explanation:

Given table is

Yes No Don't Know Total

Men 162 92 25 279

Women 258 41 11 310

Total 420 133 36 589

According the the conditional probability, if A and B are two event then

$P(A|B)=P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}$

We need to find the following probabilities.

Let Y is the event "saying yes," and M is the event "being a man."

(a)

$P(Y'|M)=\frac{P(Y'\cap M)}{P(M)}$

$P(Y'|M)=\frac{\frac{92}{589}}{\frac{279}{589}}$

$P(Y'|M)=\frac{92}{279}$

$P(Y'|M)=0.329749103943$

$P(Y'|M)\approx 0.3297$

(b)

$P(Y|M')=\frac{P(Y\cap M')}{P(M')}$

$P(Y|M')=\frac{\frac{258}{589}}{\frac{310}{589}}$

$P(Y|M')=\frac{258}{310}$

$P(Y|M')=0.832258064516$

$P(Y|M')\approx 0.8323$

(c)

$P(Y'|M')=\frac{P(Y'\cap M')}{P(M')}$

$P(Y'|M')=\frac{\frac{41}{589}}{\frac{310}{589}}$

$P(Y'|M')=\frac{41}{310}$

$P(Y'|M')=0.132258064516$

$P(Y'|M')\approx 0.1323$

5 0

3 years ago