15/30 divided by 15/15
2 answers:
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Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
=
But this distance needs to be betweem 50 & 60
So
Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
=
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
For this case we have the following inequality:
3y - 2x> 8
The first thing we should do is to graph the function.
Then, see the set of points that are the solution of the inequality.
The solution set is given by the shaded region.
See attached image.
Answer:
Shaded region.
See attached image.
3y - 2x> 8
The first thing we should do is to graph the function.
Then, see the set of points that are the solution of the inequality.
The solution set is given by the shaded region.
See attached image.
Answer:
Shaded region.
See attached image.