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Neko [114]
3 years ago
14

1) Which answer is a solution of the equation? 2x-y=5

Mathematics
1 answer:
Montano1993 [528]3 years ago
4 0
For the first one it's D. and the second one is D. as well

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Which of the following is most likely the next step in the series
Anna35 [415]

Answer:

bbbbbbbbbbbbbbbbbbbbbbbbb

8 0
2 years ago
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-6h plus 4 - 3plus h equals 11
olga55 [171]

- 6h + 4 - 3 + h = 11
So we start by combining like terms;
- 6h + h =  - 5h
4 - 3 = 1
Now we have;
- 5h + 1 = 11
We then subtract 1 from both sides;
- 5h + 1 = 11
- 5h = 10
Then we divide both sides by 5;
- 5h = 10
- 5h \div  - 5h =  h
10 \div  - 5h =  - 2
Leaving the final answer to be h = -2
5 0
4 years ago
what is the slope of the line through (1,0)(1,0)left parenthesis, 1, comma, 0, right parenthesis and (3,8)(3,8)
77julia77 [94]

The slope of the line passing through (1 , 0) and (3 , 8) is 4.

Slope, commonly represented by the letter m, is a value that describes the steepness and direction of a line. The slope of a line is also called its gradient or rate of change.

It is the vertical change in y divided by the horizontal change in x, sometimes called rise over run. The slope formula uses two points, (x_{1}, y_{1} ) and (x_{2}, y_{2} ), to calculate the change in y over the change in x.

m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1} }     where

x_{1} = 1

y_{1} = 0

x_{2} = 3

y_{2} = 8

Substituting the values,

m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1} } =\frac{8-0}{3-1} =\frac{8}{2}=4

Hence, he slope of the line passing through (1 , 0) and (3 , 8) is 4.

For more example on slope of line, visit brainly.com/question/3493733.

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7 0
2 years ago
Words problems involving length and money
stiv31 [10]

Answer:

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Since 8 poster takes 48 inches of tape

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each poster will take 6

if you have two posters

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so 12

5 0
2 years ago
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Using the work shown on the left, What is the cubed root of 4/ the square root of 2 in simplest radical form
krek1111 [17]

Answer:

⁶√2

Step-by-step explanation:

∛4 = (2^2)^1/3 = 2^2/3

So ∛4 / √2

= 2^2/3 / 2^1/2

= 2^1/6

= ⁶√2

5 0
3 years ago
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