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2 years ago

8

Given that the universe set U = {baseball, basketball, football, tennis ball, soccer ball, volleyball} and that the set A is the

set of sports balls that are spherical, what is the complement of Set A?

1 answer:

DedPeter [7]2 years ago

3 0

2 because it is a baseball card

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Which is greater 50 Hectoliters or 10 kiloliters

Tomtit [17]

Kiloliters are bigger so if they are bigger they have to be kiloliters right>:)
10kL<span> = 100hL, so </span>10kL<span> > </span><span>50hL</span>

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3 years ago

A cheetah's speed was timed over a set distance. The cheetah was clocked running 60 miles per hour. Which equation is the relati

Troyanec [42]

Answer:

D. y=70x

Step-by-step explanation:

The cheetah was clocked running 70 miles per hour.

i.e. in 1 hour cheetah covered 70 miles

in 2 hours cheetah covered 140 miles

in 3 hours cheetah covered 210 miles

in general, in n hour cheetah covered 70n miles

If y denote the distance covered

and x denotes the time cheetah runs

Then, y=70x

Hence, the equation which shows the relationship between the distance, y, and time, x, the cheetah runs is:

D y=70x

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3 years ago

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

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3 years ago

What is a budget?<br> only a savings plan<br> savings and spending plan<br> only a spending plan

son4ous [18]

Answer:

Step-by-step explanation:

A plan to only spend x amount of money while shopping

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3 years ago

Read 2 more answers

Exterior Angles Assignment Help

Ksenya-84 [330]

Answer:

x=90º

Step-by-step explanation:

x=60+30

x=90

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3 years ago