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2 years ago

8

Given that the universe set U = {baseball, basketball, football, tennis ball, soccer ball, volleyball} and that the set A is the

set of sports balls that are spherical, what is the complement of Set A?

1 answer:

DedPeter [7]2 years ago

3 0

2 because it is a baseball card

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Each week, Christian earns $x fixing bicycles and receives $10 as his allowance. To find how much he will earn in total over 2 w

pashok25 [27]

The answer is B.
If he earns $x in one week, then you need 2x to calcualte 2 weeks, add that with his allowance and there you have it.

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2 years ago

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-2 2/3, -5 1/3, -10 2/3, -21 1/3, -42 2/3. which formula can be used to describe the sequence?

Stella [2.4K]

Your sequence appears to be geometric with a common ratio of 2. It can be described by
a(n) = (-2 2/3)·2^(n-1)

_____
This can be written in a number of other forms, including
a(n) = (-8/3)·2^(n-1)
a(n) = (-1/3)·2^(n+2)
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3 years ago

3.1 = x / 2 equals what?

neonofarm [45]

Answer: 6.2

Step-by-step explanation: 3.1 = x/2

x/2=3.1

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x=6.2

3 0

2 years ago

If m∠D = 18°, and m∠C = 45°, what is ?

Fynjy0 [20]

<span>the question is, If m∠D = 18° and m∠C = 45° what is arc BC? your answer is B. 54 degrees </span>

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3 years ago

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Which expression is equivalent

Tatiana [17]

Given expression is

$\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}$

Radical is fourth root

first we simplify the terms inside the radical

$\frac{x^{11}}{x^7}=x^4$

$\frac{y^(8)}{y^6}=y^2$

So the expression becomes

$\sqrt[4]{\frac{16x^4y^2}{81}}$

Now we take fourth root

$\sqrt[4]{16} = 2$

$\sqrt[4]{81} = 3$

$\sqrt[4]{x^4} = x$

We cannot simplify fourth root (y^2)

After simplification , expression becomes

$\frac{2x\sqrt[4]{y^2}}{3}$

Answer is option B

8 0

2 years ago