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OleMash [197]
2 years ago
8

Given that the universe set U = {baseball, basketball, football, tennis ball, soccer ball, volleyball} and that the set A is the

set of sports balls that are spherical, what is the complement of Set A?
Mathematics
1 answer:
DedPeter [7]2 years ago
3 0
2 because it is a baseball card
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Misha and Dontavious were asked to solve the following problem using linear programming. A local school district can operate a l
bearhunter [10]

Answer:

did you get the answer?

Step-by-step explanation:

4 0
3 years ago
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Help a girl out plsss.?
Ludmilka [50]
The last one and the first one 
hope you got it 

4 0
3 years ago
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Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160°, respectively. Find the direction and
shusha [124]
Forces in direction x:
 
fx1 = 100 * cos (50) = 64.28
 fx2 = 50 * cos (160) = - 46.99
 The resultant is:
 fx = fx1 + fx2 = 17.29

 Forces in direction y:
 
fy1 = 100 * sine (50) = 76.60
 fy2 = 50 * sine (160) = 17.10
 The resultant is:
 fy = fy1 + fy2 = 93.70
 The magnitude of the resulting force is:
 
f = root (fx ^ 2 + fy ^ 2)
 f = root ((17.29) ^ 2 + (93.70) ^ 2)
 f = 95.28
 The angle is:
 
theta = atan (fy / fx)
 theta = atan (93.70 / 17.29)
 theta = 79.55 degrees
 Answer:
 
The direction and magnitude of the resultant force are:
 
f = 95.28 pounds at theta = 79.55 degrees
6 0
3 years ago
Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
the length of a rectangle is two feet greater then twice its width if the primeter is 25 find the width
Mademuasel [1]

Answer:

Step-by-step explanation:

Perimeter is simply length + width. They gave us that the length is 2 feet plus 2 times the width:

25=(2w+2)+W

Subtract 2 from both sides to get 23 = 2w + w

Combine like terms to get 23 = 3w

Divide by 3 to get w=7 \frac{2}3} feet

7 0
3 years ago
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