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Studentka2010 [4]
3 years ago
12

Please help thank you

Mathematics
2 answers:
Bad White [126]3 years ago
8 0

Answer:

g (grams)

Step-by-step explanation:

Example

Jesse needs to decide which metric unit he should use to weigh a bowl of books and documents.

First, think about the size and weight of the objects in the bowl.

Milligrams would be far too small of a unit. The books alone would probably weigh a few million milligrams. Even grams is really not ideal, since the total weight would be thousands of grams.

Marina86 [1]3 years ago
7 0

Answer:

B.

Step-by-step explanation:

b. because its the L in the cearl bowl

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Multiply (5x^2-6x+2) x (4x^2-3x)
V125BC [204]

Answer:

20x^{4} - 39x^{3} + 26x^{2} - 6x

hope this helps

5 0
3 years ago
Rewrite this equation in Slope Intercept form and
german

Answer:

y = -2x+6

y=8  when x = -1

Step-by-step explanation:

2x + y = 6

Slope intercept form is  y = mx+b where m is the slope and y is the intercept

Solve for y

Subtract 2x from each side

y = -2x+6

The slope is -2 and the y intercept is -6

Let x = -1

y = -2(-1) +6

y = 2+6

y=8

(-1,8)

3 0
3 years ago
Read 2 more answers
How old am I if 500 reduced by 2 times my age is 388
Nimfa-mama [501]
Remember you can do anything to an equation as long as you do it to both sides
a=age

500 reduced by 2 times a is equal to 388

500-2a=388
minus 500 both sides
-2a=-112
divide both sides by -2
a=56

you are 56
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B3%7D%20" id="TexFormula1" title="\frac{3}
Scrat [10]
The answer would be 14/15

Find a common denominator that both of the fractions can use. An easy way to do this is simply multiply the denominators together. So for 3/5 you would multiply by 3 to get the fraction 9/15 and then multiply 1/3 by 5 to get 5/15. Add both 9/15 and 5/15 to then get 14/15.
4 0
3 years ago
Read 2 more answers
If
Anna11 [10]
Answer: -104

Explanation: x=-9 y=2
2(y-3xy)
=2(2-3(-9)(2))
=4-2(3(-18))
=4-108
=-104

Hope it helped

4 0
2 years ago
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