Question

I know the answer just need someone explain to me how to solve it

Answer 1

The logarithm of a quotient can be written as a difference of logarithms:

$\log_3\left(\dfrac uv\right) = \log_3(u) - \log_3(v)$

You can also think of this as a combination of the product-to-sum and reciprocal/power properties of logarithms:

$\log_3\left(\dfrac uv\right) = \log_3\left(u \times \dfrac1v\right) = \log_3(u) + \log_3\left(\dfrac1v\right) = \log_3(u) - \log_3(v)$

To summarize,

$\log_b(mn) = \log_b(m)+\log_b(n)$

$\log_b\left(\dfrac mn\right) = \log_b(m) - \log_b(n)$

$\log_b\left(m^n\right) = n \log_b(m)$