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BigorU [14]
3 years ago
11

Suppose a day from this city is selected at random. Let event A = heavy traffic and event B = bad weather. Are events A and B in

dependent? O No, P(A) = P(BIA). O No, P(A) # P(A|B). O Yes, P(A) = P(A|B). O Yes, P(A) # P(BIA),
Mathematics
1 answer:
Studentka2010 [4]3 years ago
5 0

No, the two events A and B are not independent. Event A is heavy traffic and Event B is bad weather. They both are dependent to each other.

<h3>How to find if two events are independent?</h3>

Suppose that two events are denoted by A and B. They are said to be an independent event if and only if:

P(A \cap B) = P(A)P(B)

It is because

P(A|B) = P(A)\\P(B|A) = P(B)

and therefore, using chain rule and above facts gives:

P(A \cap B) = P(A)P(B)

Let event,

Event A = heavy traffic

Event B = bad weather

Only when one event affects the other is a pair of occurrences considered to be independent.

The two occurrences are not independent in this case.

Heavy rains, snowfall, and other extreme weather conditions cause traffic systems to fail, resulting in gridlock. This is seen in all major metropolitan areas.

As a result, the two activities are not independent, since weather conditions impact traffic.

To learn more about the independent event, refer to the link;

brainly.com/question/13488890

#SPJ1

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Is the relation depicted in the chart a function? Yes or No? Why or why not?
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Answer:

yes

Step-by-step explanation:

x+1 and y+1 it is consistent the equation looks like 1(x)+ 8

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3 years ago
Simplify r^6 • r^5 type your answer in the box
TEA [102]

Answer:

r^11

Step-by-step explanation:

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3 years ago
John, Sally, and Natalie would all like to save some money. John decides that it would be best to save money in a jar in his clo
Radda [10]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) y=100x+300

Part 3) \$12,300

Part 4) Is a exponential growth function

Part 5) A=6,000(1.07)^{t}  

Part 6) \$11,802.91  

Part 7) Is a exponential growth function

Part 8) A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}  

Part 9)  \$13,591.41

Part 10) Natalie has the most money after 10 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

m=\$100\ per\ month

The y-intercept or initial value is

b=\$300

so

y=100x+300

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

y=100x+300

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

10 years=10(12)=120 months

For x=120 months

substitute in the linear equation

y=100(120)+300=\$12,300

Part 4) What type of exponential model is Sally’s situation?

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

P=\$6,000\\ r=7\%=0.07\\n=1  

substitute in the formula above

A=6,000(1+\frac{0.07}{1})^{1*t}  

A=6,000(1.07)^{t}  

therefore

Is a exponential growth function

Part 5) Write the model equation for Sally’s situation

A=6,000(1.07)^{t}  

see the Part 4)

Part 6) How much money will Sally have after 10 years?

For t=10 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{10}=\$11,802.91  

Part 7) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

P=\$5,000\\r=10\%=0.10  

substitute in the formula above

A=5,000(e)^{0.10t}  

Applying property of exponents

A=5,000(1.1052)^{t}  

therefore

Is a exponential growth function

Part 8) Write the model equation for Natalie’s situation

A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

see Part 7)

Part 9) How much money will Natalie have after 10 years?

For t=10 years

substitute

A=5,000(e)^{0.10*10}=\$13,591.41

Part 10) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

4 0
4 years ago
Read 2 more answers
Graph the function y = 4x4 – 8x2 + 4. Which lists all of the turning points of the graph?
Serhud [2]

Answer:

4(x + 1)^{2}(x - 1)^{2}

Step-by-step explanation:

STEP 1:

The equation at the end of step 1

((4 (x^4)) -  2^3x^2) +  4

STEP 2:

The equation at the end of step 2:

(2^2x^4 -  2^3x^2) +  4

STEP 3:

STEP 4: Pulling out like terms

<u>4.1</u> Pull out like factors:

4x^4 - 8x^2 + 4  =   4(x^4 - 2x^2 + 1)

Trying to factor by splitting the middle term

<u>4.2</u> Factoring x^4 - 2x^2 + 1

The first term is, x^4 its coefficient is 1.

The middle term is,  -2x^2  its coefficient is -2.

The last term, "the constant", is +1.

Step-1: Multiply the coefficient of the first term by the constant   1 • 1 = 1

Step-2: Find two factors of  1  whose sum equals the coefficient of the middle term, which is -2.

-1 + -1 = -2 That's it

Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -1  and  -1

                    x4 - 1x2 - 1x2 - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x2 • (x2-1)

             Add up the last 2 terms, pulling out common factors :

                    1 • (x2-1)

Step-5 : Add up the four terms of step 4 :

                   (x2-1)  •  (x2-1)

            Which is the desired factorization

Trying to factor as a Difference of Squares:

4.3      Factoring:  x2-1

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1

Check :  x2  is the square of  x1

Factorization is :       (x + 1)  •  (x - 1)

Trying to factor as a Difference of Squares:

4.4      Factoring:  x2 - 1

Check : 1 is the square of 1

Check :  x2  is the square of  x1

Factorization is :       (x + 1)  •  (x - 1)

Multiplying Exponential Expressions:

4.5    Multiply  (x + 1)  by  (x + 1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (x+1)  and the exponents are :

         1 , as  (x+1)  is the same number as  (x+1)1

and   1 , as  (x+1)  is the same number as  (x+1)1

The product is therefore,  (x+1)(1+1) = (x+1)2

Multiplying Exponential Expressions:

4.6    Multiply  (x-1)  by  (x-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (x-1)  and the exponents are :

         1 , as  (x-1)  is the same number as  (x-1)1

and   1 , as  (x-1)  is the same number as  (x-1)1

The product is therefore,  (x-1)(1+1) = (x-1)2

Final result :

 4 • (x + 1)2 • (x - 1)2

4 0
3 years ago
Read 2 more answers
Find, as a ratio, the scale of a map given as 2cm to 1km. If two towns are 23.4cm apart on the map, what is the actual distance
Rina8888 [55]

Answer:

The actual distance is 11.7km

Step-by-step explanation:

2cm = 1km

1cm = 0.5km

23.4cm = ?

23.4 × 0.5 = 11.7km

(Correct me if i am wrong)

8 0
3 years ago
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