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Fudgin [204]
3 years ago
15

Find, as a ratio, the scale of a map given as 2cm to 1km. If two towns are 23.4cm apart on the map, what is the actual distance

between them?
Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:

The actual distance is 11.7km

Step-by-step explanation:

2cm = 1km

1cm = 0.5km

23.4cm = ?

23.4 × 0.5 = 11.7km

(Correct me if i am wrong)

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Solve pls for brainliest
Luden [163]

Answer:

19. 6561

20. 196

22. \frac{256}{25}

23. \frac{1}{16}

24. \frac{2}{9}

5 0
3 years ago
A rental car agency charges $220.00 per week plus 50.15 per mile to rent a car. How many miles can you travel in one week for $3
babymother [125]

Answer:2.81

Step-by-step explanation:

First you subtract the per week (220) from your budget (361)

You get 141

You now divide 141 by 50.15

You come out to 2.81

This means you can drive up to 2.81 miles but no more

8 0
3 years ago
I honestly don't even know where to start //// on his last 4 tests , Danilo scored 55% 78% 84% and 93%. What score should he get
skelet666 [1.2K]

Answer:

The answer to your question is He must get 80%

Step-by-step explanation:

Data

Scores 55%, 78%, 84%, 93% and X

Average 80%

Process

1.- Write a equation to solve this problem

- There are five scores

Score 1 = S1 = 55

Score 2 = S2 =  78

Score 3 = S3 = 84

Score 4 = S4 = 93

Score 5 = S5 = X

Equation

               Average = (S1 + S2 + S3 + S4 + S5) / 5

- Solve for S5

               5 Average = S1 + S2 + S3 + S4 + S5

               S5 = 5 Average - S1 - S2 - S3 - S4

- Substitution

               S5 = 5(80) - 55 - 78 - 84 - 93

- Simplification

               S5 = 400 - 310

- Result

               S5 = 90

5 0
3 years ago
The quality-control manager at a compact flourescent light bulb factory wants to test the claim that the mean life of a large sh
MAXImum [283]

Answer:

a. At the 0.05 level of significance,  there is evidence that the mean life is different from 6,500 hours.

b. The p value= ≈ 0.00480 for z- test which is less than 0.05 and H0 is rejected .

The p value= 0.006913 for t- test which is less than 0.05 and H0 is rejected for 49 degrees of freedom.

c. CI [6583.336 ,6816.336]

d.  The range of CI [6583.336 ,6816.336] tells that the cfls having a different mean life lie in this range.

Step-by-step explanation:

Population mean = u= 6500 hours.

Population standard deviation = σ=500 hours.

Sample size =n= 50

Sample mean =x`=  6,700 hours

Sample standard deviation=s=  600 hours.

Critical values, where P(Z > Z) =∝ and P(t >) =∝

Z(0.10)=1.282  

Z(0.05)=1.645  

Z(0.025)=1.960  

t(0.01)(49)= 1.299

t(0.05)= 1.677  

t(0.025,49)=2.010

Let the null and alternate hypotheses be

H0: u = 6500 against the claim Ha: u ≠ 6500

Applying Z test

Z= x`- u/ s/√n

z= 6700-6500/500/√50

Z= 200/70.7113

z= 2.82=2.82

Applying  t test

t= x`- u /s/√n

t= 6700-6500/600/√50

t= 2.82

a. At the 0.05 level of significance,  there is evidence that the mean life is different from 6,500 hours.

Yes we reject H0  for z- test as it falls in the critical region,at the 0.05 level of significance, z=2.82 > z∝=1.645

For t test  we reject H0   as it falls in the critical region,at the 0.05 level of significance, t=2.82 > t∝=1.677 with n-1 = 50-1 = 49 degrees of freedom.

b. The p value= ≈ 0.00480 for z- test which is less than 0.05 and H0 is rejected .

The p value= 0.006913 for t- test which is less than 0.05 and H0 is rejected for 49 degrees of freedom.

c. The 95 % confidence interval of the population mean life is estimated by

x` ±  z∝/2  (σ/√n )

6700± 1.645 (500/√50)

6700±116.336

6583.336 ,6816.336

d. The range of CI [6583.336 ,6816.336] tells that the cfls having a different mean life lie in this range.

6 0
3 years ago
Which two triangles are similar?
Alla [95]

Answer:

A and C are similar

Step-by-step explanation:

The sum of a triangles angles = 180

If you calculate the remaining angles, you will see that both A and C have the same angles and therefore are similar.

6 0
2 years ago
Read 2 more answers
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