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liberstina [14]
2 years ago
13

Why are scientists not able to agree on whether or not viruses are alive?

Biology
1 answer:
EleoNora [17]2 years ago
7 0

Answer:

A .Viruses cannot evolve but can infect living cells.

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Write a paragraph on testing probability
VashaNatasha [74]

Explanation:

Probabilities are described as ratios of favorable event outcome to the total number of event outcomes.

This is written as...

P (E) =\frac{n(E)}{n(S)} \\

where...

E= the number of times the event occurs

S= the number of trials

In biology experiments, hypotheses are formed based on research questions, and tested with the use of variables  to provide a particular outcome. Statistics allows for testing data for consistency with the hypothesis, while statistical probability testing can be used in experiments to determine a range of outcomes, from genetic inheritance, evolutionary rates to theoretical experimental results.

In these statistical models, probability distributions are functions that give probabilities for certain event outcomes within an experiment (a set of trials). These may be either continuous, taking a value within a range of two numbers; or discrete, which may be either of two specified values. Discrete probability distributions list each value that a random variable may possibly take on.

Further Explanation:

For example, two types of probability distributions are employed in experimental biology:

Binomial distributions, which are discrete distributions,  provide probability of a certain number of successful events for x  a random variable, in a specific number of trials, n; here, the probability of success of an individual trial is constant at P and only one of two outcomes are possible- this is sampling with replacement.

where...

b(x;  n, P)-the probability that an experiment of n trials results in x successes

nCx- the number of combinations of n things at r time

b(x;  n, P) = [ nCx ]* P^{x}  * (1-P)^{n-x}\\

<em>This is often used in determining potential outcomes before data collection.</em>

A type of continuous distribution, the student's t-test, compares standard deviations and means from two sets of samples or groups to check for significant differences between them.

t= \frac{(x_{1} - x_{2}) }{\sqrt{(\frac{(S_{1}) ^{2} }{n1} }+ (\frac{(S_{2}) ^{2} }{n2 }}

where...

  • x1 and s1 are the mean and standard deviation of sample 1 respectively
  • x2 and s2 are the mean and standard deviation of sample 1 respectively  
  • n1 and n2 are sample sizes in samples 1 and 2 respectively

The null and alternate hypotheses typically theorize the likelihood and significance of certain event outcome probabilities. Critical values of t, along with degrees of freedom are used to determine a range of probable outcomes; probability or p- values along with this range, are used to determine whether either hypothesis is rejected or accepted.

<em>For instance, significant differences between an experimental control and a specific treatment group would show that these occurrences are not due to sampling errors or random chance...</em>

Learn more about calculating probability at brainly.com/question/4021035

Learn more about calculating event probability at brainly.com/question/6649771

#LearnWithBrainly

5 0
3 years ago
In the 1600s, which scientist discovered microbes in pond water by using a microscope
Nikitich [7]
It was Robert Hooke.
7 0
3 years ago
Read 2 more answers
Development refers to the increase in size of an individual<br><br> true <br> false
nlexa [21]

Answer: true

Explanation: Growth refers to change in size, like weight or length. Development refers to changes in physical, social, emotional, and intellectual abilities.

7 0
2 years ago
Read 2 more answers
2. Dominant trait: cleft chin (C) Mother’s gametes: Cc
kakasveta [241]

Answer No 2:

      c      c

C   Cc     Cc

c    cc      cc

The genotype of the offsprings would be Cc, Cc, cc, cc i.e heterozygous cleft chin and no cleft chin. The phenotype of the offsprings could be 50% cleft chin and 50% without cleft chin.

there will be 50% chance of the child to have cleft chin.

Answer No 3:

        A        a

A     Aa       Aa

a      Aa        aa

There will be 25% chance for the offspring to have arched feet. As arched feet is a recessive trait, so for this trait to occur both the alleles of the gene should be recessive i.e aa.

Answer No 4:

    B      b

b   Bb    bb

b    Bb    bb

As blonde is a recessive trait, so both the alleles for this gene should be recessive for this trait to occur. Hence, according to the punnet square, there will be 50% chance for the offspring to be blonde.

Answer No 5:

           F      f

F          FF    Ff

f           Ff     ff

As normal vision is a resessive trait, hence both the alleles of the gene should be recessive for the trait to occur. According to the punnet square, there is 25% chance that the child will have normal vision.

3 0
3 years ago
Cuál sería el problema con relación a los camélidos sudamericanos y a los biocombustibles (considerar aspectos sociales,  aspect
AysviL [449]
Hi I can help you with your problem
3 0
3 years ago
Read 2 more answers
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