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2 years ago

14

Write the equation of the following graph in intercept form.

1 answer:

Kobotan [32]2 years ago

8 0

Answer:

A) $f(x)=0.2(x+2)(x-5)$

Step-by-step explanation:

The graph has x-intercepts at $x=5$ and $x=-2$ , so our factors for the polynomial will be $x+2$ and $x-5$ . This means we can rule out options B and D.

Our graph also has a y-intercept of $y=-2$ when $x=0$ , so if we let $f(x)=-2$ and $x=0$ , we can find the multiplier:

$f(x)=a(x+2)(x-5)\\-2=a(0+2)(0-5)\\-2=a(2)(-5)\\-2=-10a\\\frac{1}{5}=a\\0.2=a$

Thus, the correct equation is A) $f(x)=0.2(x+2)(x-5)$

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The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

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P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

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$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

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2 years ago