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Flauer [41]
2 years ago
6

Explain why the graph may have values for years that are still in the future

Mathematics
1 answer:
avanturin [10]2 years ago
8 0

Answer:

so poople in the future can extend the graph instead of making a new one

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Lonna had 30 minutes to do a three-problem quiz. She spent 11 minutes on question A and 4
STatiana [176]

Answer:

She had 15 minutes left.

Step-by-step explanation:

30 - 11 = 19

19 - 4 = <em>15</em>

8 0
3 years ago
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A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in​ ft/s. The rang
VARVARA [1.3K]

Answer:

\theta=24.4^\circ

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range​ of a projectile is in reality approximated by the equation x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta), where we will use ft for distances.

From the given equation we have then \frac{x32ft/s^2}{v^2} =sin(2\theta), which means \theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2} since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and  v = 85 ft/s, we can substitute these values from the equation written, and we will have \theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}, and from now on we have just to use a calculator, obtaining \theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ

3 0
3 years ago
The following histogram shows the number of items sold at a grocery store at various prices:
monitta

Answer:

<h2><u><em>its B</em></u></h2>

Step-by-step explanation:

8 0
3 years ago
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a rectangle of perimeter 100 units has the dimensions shown. Its area is given by the function A = w(50 - w). What is the GREATE
Anna [14]
If A=w(50-w)

A=50w-w^2

dA/dw=50-2w

d2A/dw2=-2

Since the acceleration is a constant negative, that means that when velocity, dA/dw=0, it is at an absolute maximum for A(w)...

dA/d2=0 only when 50=2w, w=25

So as the case with any rectangle, the perfect square will enclose the greatest area possible with respect to a given amount of material to enclose that area...

So the greatest area occurs when W=L=25 in this case:

A(25)=50w-w^2

Area maximum is thus:

Amax=50(25)-(25)^2=625 u^2
7 0
3 years ago
Use “decomposing” to answer the questions below
Degger [83]
A) 36
B)6
If you need help with More math let me know I’m a straight A student in math
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3 years ago
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