{12÷(9−6)}+4×6{12÷(9−6)}+4×6
1 answer:
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Answer:
13.86 ft/sec
Step-by-step explanation:
If we let x = distance batter has run at time t and D = distance from second base to the batter at time t, then we know and we want
when he is halfway (at x = 45).
Using Pythagoras theorem
When x=45
Thus, when the batter is halfway to first base, the distance between second base and the batter is decreasing at the rate of about 13.86 ft/sec.
Answer:
x =
Step-by-step explanation:
Use Pythagorean theorem,
Hypotenuse² = base² + altitude²
x² = (√8)² + 4²
= 8 + 16
= 20
x = √20 =
x =