Hello!
To find how much batches of cookies the factory made, we need to divide the total number of bags of flour used by how many bags of flour are needed for one batch of cookies.
Before dividing, we need to convert the complex fraction into an improper fraction.
1 1/5 → 5 × 1 + 1 = 6/5
7 1/5 → 5 × 7 + 1 = 36/5
For every batch of cookies, the factory uses 6/5 bags of flour. Yesterday, the factory used 36/5 bags of flour.
Remember when dividing by a fraction, it is like multiplying its reciprocal. This means that the second fraction is flipped, then which it can be multiplied together.
→ 
Therefore, the cookie factory made 6 batches of cookies yesterday.
The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked 
miles.
<u>Solution:</u>
Given that,
- Julian walked 6/10 of a mile to his friends house
- Another 35/100 mile to the store
- He walked 1/4 of a mile back home
To find total distance walked by Julian we have to add the above stated values. That is, 
Factors of 10 = 
Factors of 100 = 
Factors of 4 = 
Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,
Which can also be written as 
.
So, from the above calculation it can be said that Julian walked 
.
What I did was add all the x's since you are trying to find the perimeter then I got 16 and then you add the whole numbers. 16x+3
The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
