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photoshop1234 [79]
1 year ago
13

What percent of 12 is 15?​

Mathematics
2 answers:
ozzi1 year ago
4 0

Answer:

125%

Step-by-step explanation

125% of 12 is 15

matrenka [14]1 year ago
4 0

Answer:

0.8 or 80%

Step-by-step explanation:

12/15=0.8 or 80%

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Answer: it’s A

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for a walk-a-thon a sponsor committed to give to give you a flat fee of $5 plus $2 for every Mile you walk write an expression f
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Please answer this question for points
alexgriva [62]

Answer:

<h2>y = -2x + -3</h2>

Step-by-step explanation:

Slope-intercept form is y = mx + b

"m" is the slope, how steep the line is.

"b" is the y-intercept, where to graph hits the y-axis.

Check the scale for this grid. Since there are "1" written on the first box after the middle, <u>one square = one unit</u>.

To find "m", use  m = \frac{rise}{run}   between the two dotted points on the graph. The first point is always on the left.

<u>"Rise" means how many squares above</u> the first point the second point is.

Since the second point is below the first point, the number is negative.

<u>"Run" means how many squares to the right</u> the second point is.

m = \frac{rise}{run}          

m = \frac{-2}{1}

m = -2

To find "b", look at where the graph it touching the y-axis.

The y-axis is the vertical line (going from top to bottom).

Count the number of squares from the grid's middle to the graph line.

There are 3 squares.

Since the graph touches below the origin, this is a negative number.

b = -3

In the boxes, you put negative two (-2) and negative three (-3).

* Usually we would simplify the equation to y = -2x - 3.

6 0
3 years ago
Solve for x, 3x^2 x x - 5=0
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Answer:

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this is answerrr

5 0
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Which second-degree polynomial function has a leading coefficient of –1 and root 5 with multiplicity 2?
PIT_PIT [208]
A second degree polynomial function has the general form:

                  \displaystyle{f(x)=ax^2+bx+c, where a\neq0.

The leading coefficient is a, so we have a=-1.

5 is a double root means that :

i) f(5)=0,
ii) the discriminant D is 0, where D=b^2-4ac.

Substituting x=5, we have

                                        f(5)=a(5)^2+b(5)+c,

and since f(5)=0, and a is -1 we have:

                                          0=-25+5b+c
thus c=25-5b.


By ii) \displaystyle{b^2-4ac=0.

Substituting a with -1 and c with 25-5b we have:
                                     
          \displaystyle{b^2-4ac=0
          \displaystyle{b^2-4(-1)(25-5b)=0
          \displaystyle{b^2+4(25-5b)=0
          \displaystyle{b^2-20b+100=0
          \displaystyle{(b-10)^2=0
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Finally we find c: c=25-5b=25-50=-25

Thus the function is        \displaystyle{f(x)=-x^2+10x-25


Remark: It is also possible to solve the problem by considering the form

f(x)=-1(x-5)^2 directly.

In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is f(x)=a(x-r)^2
5 0
2 years ago
Read 2 more answers
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