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3 years ago

6

Fred's boat rental charges a rental fee of $30 plus $5 per hour. Joe's boat rental charges a flat rate of $20 an hour. Set the s

ituations up as an equation and find the number of hours for which the total amount that both places charge would be the same.

1 answer:

zmey [24]3 years ago

8 0

30 + 5h = 20h
30 = 20h - 5h
30 = 15h
30/15 = h
2 = h

at 2 hrs, they both charge the same rate...
30 + 5(2) = 30 + 10 = 40
20h = 20(2) = 40
so at 2 hrs, they both charge $ 40

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The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

a

$336.04 < \mu < 443.96$

b

The margin of error will increase

c

The margin of error will decreases

d

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

So

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

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3 years ago

What is the area of this triangle 20 POINTS

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Answer:

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Step-by-step explanation:

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6.8 is what i got for the answer

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3 years ago

A prism with a length of 4 inches, height of 4 inches, and width of 3 inches. How many more 1 in. cubes does the container need

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There are 10 number of 1 cubic inches box required to fill the container completely.

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It is defined as the six-faced shape, a type of hexahedron in geometry.

It is a three-dimensional shape.

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A prism with a length of 4 inches, height of 4 inches, and width of 3 inches.

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Here some data are missing.

We are assuming there are 38 1 cubic inches box already in the big box.

So,

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2 years ago

Find the MAD for this set of data.

Nostrana [21]

Answer:

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Step-by-step explanation:

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MAD is also known as Mean Absolute Deviation.

We find MAD by the following steps:

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Now we are given a table of the absolute deviation we just need to calculate the mean of the absolute deviation.

The absolute deviation is given as:

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Hence, MAD=0.8

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3 years ago

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