So
if you assume that the month has 30 days and that the library opens at midnight, then
24 hours in a day
5 pm=12+5=17 hours
on wednessday=17-2=15 hours
wednessday=1/7 of week
so we find 1/7 of 30 which is 30/7=4 and 2/7
then subtract that from 30
30-4 and 2/7=25 and 5/7
ok so then we have
25 and 5/7 days is 17 hours and
4 and 2/7 days is 15 hours
so just multipy them and add
25 and 5/7 times 17=437.143 hours
4 and 2/7 days times 15 =64.2857
add
437.143+64.2856=501.429
so aprox 501.429
the real equation is
![[(\frac{1}{7})(n)(15)]+[ (\frac{6}{7}) (n)(17)]=hours](https://tex.z-dn.net/?f=%5B%28%5Cfrac%7B1%7D%7B7%7D%29%28n%29%2815%29%5D%2B%5B%20%28%5Cfrac%7B6%7D%7B7%7D%29%20%28n%29%2817%29%5D%3Dhours)
where n represents the number of days in the month
apros 501.429
Answer:
D.
Step-by-step explanation:
the graph has a y intercept of -3
try substituting any point in one of the equations that fit the graph in this one that is D.
try(1,1)
1<1-3
1<-3
it is false so shade the outside of the graph
hope it helps
Answer: 0.0023
Step-by-step explanation:
Let X be the binomial variable that represents the number of receipts will show that the above three food items were ordered.
probability of success p = 32% = 0.32
Sample size : n= 10
Binomial probability function :
Now, the probability that eight receipts will show that the above three food items were ordered :

hence, the required probability = 0.0023
Answer:
It B ok
Step-by-step explanation:
Answer: There is a probability of 0.05 that there is neither truck is available.
Step-by-step explanation:
Since we have given that
Probability that the first truck is available = 0.75
Probability that the second truck is available = 0.50
Probability that both trucks are available = 0.30
So, probability that either first truck or second truck is available is given by

We need to find the probability that neither truck is available.
so, P(A∪B)'=1-P(A∪B)

Hence, there is a probability of 0.05 that there is neither truck is available.