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Lemur [1.5K]
2 years ago
13

I NEED HELP!!!!

Mathematics
1 answer:
Ratling [72]2 years ago
7 0

Answer:

8. False.

11 and 13 are consecutive prime numbers, but 11 + 13 = 24 and 24 isn't prime.

9. True.

10. True.

11. True

12. False.

|-3+1|= 2\\|-3|+|1|=4

13. True.

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Kendra bought a magazine for $3 and four paperback books for $5 each the expression 3 + 4 x 5 represents the total cost in dolla
Elodia [21]
I´m pretty sure that the terms would just be 3, 4, and 5. It depends what kind of problem it is. 
3 0
3 years ago
Tristan is volunteering at the animal shelter one of his responsibilities is to give each of the 5 dogs their medicine each day
vova2212 [387]

Answer:

2.22

Step-by-step explanation:

4/9 x 5

4 0
2 years ago
What is the y-intercept of the graph of the function f(x) = x2 + 3x + 5?
OLga [1]
Hello there!

How do you find the y-intercept?

Answer: To find the y-intercept, substitute in 0 for x and solve for y

y = x² + 3x + 5

y = (0)²  + 3(0) + 5

y = 0 + 0 + 5

y = 5

Thus, the correct answer is option D (0,5)

I really hope this answer is clear enough for you to understand. If you have questions about the answer, please let me know.

As always, I'm glad to be your helper this evening~!
3 0
2 years ago
Read 2 more answers
Add-ons Helplast edit was seconds ago
aleksandr82 [10.1K]
Eeeeeeeeeeeeeeeeee eeeeeeeeeeeeeeeee
6 0
3 years ago
Factor completely:<br>64 - y^3
madam [21]
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is 4^{3}, and y^{3}.

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are a^{3} and b^{3}. The difference of those two cubes is:
a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})

In our problem, a = 4 (since a^{3} = 64) and b = y (since b^{3} = y^{3}. Plug these values into the rule to find the factor of 64 - y^3:
64 - y^3 \\&#10;= (4 - y)( 4^{2} + 4y + y^{2}) \\&#10;=  (4 - y)( 16 + 4y + y^{2})

-----

Answer: (4 - y)( 16 + 4y + y^{2})

8 0
2 years ago
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