Answer:
8 inch³
Step-by-step explanation:
Side should be 2 inch
Volume = side³ = 2³ = 8 inch³
Answer:
16
Step-by-step explanation:
bruh, it's right there
We are given with two equations bearing a square root sign within. In this case, the goal of f(x) is to have a value of x not greater than 1 and not less than -1. g(x) should have x only equal to positive numbers. Hence the domain for (f+g) is equal to the positive numbers greater than or equal to 1.in 2. we multiply both functions to give sqrt of x*(1-x2). the domain should be also positive numbers greater than or equal to 1.
Given:
A figure that contains a right triangular prism and cuboid.
To find:
The volume of the figure.
Solution:
The dimensions of cuboid are 16 in, 7 in and 3 in.
So, the volume of the cuboid is:



The base of the prism is a right angle with base 3 in and height 5 in, and the length of the prism is 6 in. So, the base are of the prism is



The volume of a prism is:

Where, B is the base area and h is the height of the prism.


The volume of combined figure is:



Therefore, the volume of the figure is 381 cubic in.
Diagram of two triangles
The two triangles are similar because they are both right triangles, meaning that one angle is 90° and the other two are acute (less than 90°).
The diagram on the left is missing its hypotenuse - the variable <em>c</em><em>.</em><em> </em>The hypotenuse is opposite of the right angle. The diagram on the right side is missing one of its legs.
Note: The hypotenuse is the <em>longest</em><em> </em>side of a right triangle.
Word Problen
The legs are 21 blocks and 20 blocks because they are by the right angle. Use the Pythagorean theorem to find the diagonal path's length, which is the hypotenuse.

Standard form of Pythagorean theorem.

Equation with the legs substituted and the missing hypotenuse value - <em> </em><em>c</em><em>.</em>

Square the legs and add.


Take the square root and simplify. The square root of 841 is 29 and -29, but distance is positive.
Thus the diagonal distance is 29 blocks.
Check by substituting.