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zlopas [31]
3 years ago
6

For a standard normal distribution, find the approximate value of P (negative 0.78 less-than-or-equal-to z less-than-or-equal-to

1.16). Use the portion of the standard normal table below to help answer the question.
z
Probability
0.00
0.5000
0.16
0.5636
0.22
0.5871
0.78
0.7823
1.00
0.8413
1.16
0.8770
1.78
0.9625
2.00
0.9772

A 22%
B 66%
C 78%
D 88%
Mathematics
1 answer:
Elden [556K]3 years ago
5 0

Answer

its b

Step-by-step explanation:

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8 0
3 years ago
A city hosted a music festival that included three concerts. According to the sales database, 28% of the audience attended the f
Vitek1552 [10]

Answer:

P(X\cap Y\cap Z)=0.05

Step-by-step explanation:

From the question we are told that:

Percentage of audience in first concert P(X)=0.28

Percentage of audience in second concert P(Y)=0.42

Percentage of audience in third concert P(Z)=0.30

Audience Percentage at at-least one concert P(X \cup Y \cup Z)=0.80

Percentage of audience at first & second concert P(X \cap Y)=0.10

Percentage of audience in first & third concert P(X \cap Z)=0.08

Percentage of audience in second & third concert P(Y\cap Z)=0.07

 

Generally the equation for probability of attending all concerts P(X\cap Y\cap Z)is mathematically given by

P(X \cup Y \cup Z)=P(X)+P(Y)+P(Z)-P(X \cap Y)-P(X \cap Z)-P(Y\cap Z)+P(X\cap Y\cap Z)

P(X\cap Y\cap Z)=P(X \cup Y \cup Z)-P(X)-P(Y)-P(Z)+P(X \cap Y)+P(X \cap Z)+P(Y\cap Z)

P(X\cap Y\cap Z)=0.80-0.28-0.42-0.30+0.10+0.80+0.70

P(X\cap Y\cap Z)=0.05

Therefore the probability that a randomly selected audient attended all the concerts

P(X\cap Y\cap Z)=0.05

8 0
3 years ago
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