you have to make sure that they have the same denominator so
31/4 -4 2/4
= - 1 1/4
hope this helped you hon
Answer:
A)σ = 15.37 miles per hour
B) σ = 55.10 miles per hour
C) 39.73 miles per hour
Step-by-step explanation:
Formula for standard deviation is;
σ = √(Σ(x - μ)²)/(n - 1)
A) For large wild cats;
μ = Σx/n = (70 + 40 + 30 + 40 + 35 + 35 + 35 + 35 + 10)/9 = 36.67
σ = √((70 - 36.67)² + (40 - 36.67)² + (30 - 36.67)² + (40 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (10 - 36.67)²)/(9 - 1)
σ = √236.1139
σ = 15.37
B) For various birds;
μ = Σx/n = (218 + 106 + 97 + 56 + 66 + 39 + 55 + 32 + 54 + 20 + 25 + 25)/12
μ = 66.0833
σ = √((218 - 66.0833)² + (106 - 66.0833)² + (97 - 66.0833)² + (56 - 66.0833)² + (66 - 66.0833)² + (39 - 66.0833)² + (55 - 66.0833)² + (32 - 66.0833)² + (54 - 66.0833)² + (20 - 66.0833)² + (25 - 66.0833)² + (25 - 66.0833)²)/(12 - 1)
σ = √3035.72
σ = 55.10
C) difference in standard deviations = 55.10 - 15.37 = 39.73 miles per hour
Answer:
- f = -2/5a +14
- 12.4 ≈ 12 fish for 4 algae blooms
Step-by-step explanation:
The 2-point form of the equation for a line is useful when you are given two points to work with:
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
The independent variable (x) is apparently "algae blooms" and is to be represented by "a". The dependent variable (y) is "number of fish" and is to be represented by "f". So, we have ...
f = (4 -10)/(25 -10)(a -10) +10
f = -6/15(a -10) +10
f = -2/5a +14 . . . an equation for the scenario
Four a=4, the fish population is predicted to be ...
f = -2/5(4) +14 = 12.4
There will be about 12 fish when there are 4 algae blooms.
Answer:
2 workers = 6 days
4 workers = 3 days
Step-by-step explanation:
If it takes 2 workers 6 days, if you seep up the process with 4 workers, you would divide the days by 2 because you multilpied the workers by 2. So, it would take 3 days with 4 workers. I hope that makes sence.
Answer:
-6.8125
Step-by-step explanation:
Convert 13/16 to a decimal.
Write -6 down
You get -6.8125.
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Good luck on whatever you are doing.