Question

A spinner has 6 equal sections labeled P, Q, R, S, T, and U.

Answer 1

The spinner illustrates a fair probability because it has equal sections and the value of P(Not T)= 5/6

How to determine the probability?

The sample space of the spinner is:

S = {P,Q,R,S,T,U}

Using the sample space, the probability of T is:

P(T)  = 1/6

Using the complement probability formula, the probability of not T is:

P(Not T)= 1 - P(T)

So, we have:

P(Not T)= 1 - 1/6

Evaluate

P(Not T)= 5/6

Hence, the value of P(Not T)= 5/6

Read more about probability at:

brainly.com/question/25870256

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