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Llana [10]
3 years ago
11

A student has four sticks of wood that measures 3 inches, 4 inches, 5 inches, and 6 inches.Can the student use any three of thes

e sticks to make a right triangle? Explain why or why not.
Mathematics
1 answer:
saw5 [17]3 years ago
5 0

Answer:

Yes, the student can use three of these sticks to make a right triangle.

Step-by-step explanation:

The measure of four sticks = 3 inches, 4 inches, 5 inches and 6 inches.

Now, in a right angled triangle, by PYTHAGORAS THEOREM the three sides of the triangle base, perpendicular and  hypotenuse are in the  given following relation :

(Base)^{2}  + (Perpendicular)^{2}   = (Hypotenuse)^{2}

Now, here among all four sticks

(3)^{2}  +(4)^{2}   = 9 + 16  = 25

and 25 = (5)^{2}

So, there exists three sticks of length 3 in, 4 in and 5 inches which satisft Pythagoras Theorem , such that:

(3)^{2}  + (4)^{2}   = (5)^{2}

So, the required length sticks are 3 inches, 4 inches and 5 inches.

Hence, the student use three of these sticks to make a right triangle.

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Which line in the graph has the equation y= 1/2x + 2
Alexxx [7]

Answer:

3

Step-by-step explanation:

y= mx +b

b the y-intercept and is 2  so is red or purple line

m is the slope = 1/2  so rise 1 and run 2 is the purple line

4 0
3 years ago
6 points are placed on the line a , 4 points are placed on the line b . How many triangles is it possible to form such that thei
BaLLatris [955]

Answer:

96

Step-by-step explanation:

Using side b as the base, 4 points makes 3 bases (the space in between).  With three bases, you can have 3 bases of 1 segment, 2 bases of 2 segments, and 1 base of 3 segments.  This equals 6 bases. Each of these can connect to a point on line a. 6x6=36

Using side a as the base, 6 points makes 5 bases.  With 5 bases, you can have 5 bases of 1 segment, 4 bases of 2 segments, 3 bases of 3 segments, 2 bases of 4 segments, and 1 base of 5 segments.  This equals 15 bases.  Each of these can connect to a point on line b.  15x4=60

36+60=96

5 0
3 years ago
Read 2 more answers
I need help on this pleasee​
g100num [7]

Answer:

slope is 6/0 which is undefined

Step-by-step explanation:

3 0
3 years ago
How do you work this out? need help asap
Svetlanka [38]
Hello,

Line 1 is passing through (-4,3), (-2,7) has a slope of (3-7)/(-4+2)=2

Line 2 is passing through (2,9), (4,1) has a slope of (9-1)/(2-4)=-4

One other way:

y=9-1/2 x²
y'=-x

gradient 1=-(-2)=2 for point (-2,7)

gradient 2=-(4)=-4 for point(4,1)



6 0
3 years ago
A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of
Eva8 [605]

Answer:

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

Step-by-step explanation:

Data given and notation

\bar X=250000 represent the sample mean  

s=37500 represent the standard deviation for the sample

n=5 sample size  

\mu_o =210250 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:  

Null hypothesis:\mu \leq 210250  

Alternative hypothesis:\mu > 210250  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

Conclusion

Since is a one right tailed test the p value would be:  

p_v =P(t_{4}>2.37)=0.038  

If we compare the p value and a significance level assumed \alpha=0.1 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.  

6 0
3 years ago
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