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Ugo [173]
2 years ago
15

What is the range of the function y = 2sin x?

Mathematics
1 answer:
fiasKO [112]2 years ago
5 0

The standard form of equation for the sin function is y = Asin(Bx-C) where A is amplitude, Period is 2π/B, and the phase shift is equal to Bx-C set to zero. C is then obtained in this equation.

For given problem: A is equal to 2, period=2π/B=2π/1=2π, where B is equal to 1. Period then is equal to A. 2pi

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A purchaser paid $1,539.13 for a computer system that originally cost $1,215.91. If the markup was 21% of the $1,539.13 selling
liubo4ka [24]

Answer:

$1272.008264

Step-by-step explanation:

If the mark-up was 21%, then the final price is 121% of the original price.  Simply divide $1,539.13 by 1.21 to get the original price of $1272.008264

7 0
3 years ago
The local high school is hosting an ice cream social for new students. They
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the answer is 3/7

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If Alex spends more than $150 today, he will overdraw his bank
sammy [17]

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2 years ago
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How to find factors of any numbers?
JulijaS [17]

Answer:Find all the numbers less than or equal to the given number.

Divide the given number by each of the numbers.

The divisors that give the remainder to be 0 are the factors of the number.

Step-by-step explanation:Find all the numbers less than or equal to the given number.

Divide the given number by each of the numbers.

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3 0
2 years ago
To three decimal places, find the average value of f(x) = 2x2 + 3 on the interval [0, 2].
salantis [7]
The formula for the average value of a function is \frac{1}{b-a}  \int\limits^b_a {f(x)} \, dx where b is the upper bound and a is the lower.  For us, this formula will be filled in accordingly.  \frac{1}{2}  \int\limits^2_0 {(2x^2+3)} \, dx.  We will integrate that now: \frac{1}{2}[ \frac{2x^3}{3}+3x] from 0 to 2.  Filling in our upper and lower bounds we have \frac{1}{2}[( \frac{2(2^3)}{3}+3(2))-0] which simplifies to \frac{1}{2}( \frac{16}{3}+6) and \frac{1}{2}( \frac{16}{3}+ \frac{18}{3})= \frac{1}{2}( \frac{34}{3}) which is 17/3 or 5.667
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3 years ago
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