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andrey2020 [161]
3 years ago
14

What numbers would be in the in the 4 sections of a 2 x 2 array that shows the problem 18 x 17?

Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0

In the 2 x 2 array, the sum of all squares is 18 x 17 = 306.

The number in the 4 sections are 100, 80, 70, and 56.

A 2 x 2 array that shows the problem 18 x 17.

2 x 2 array has four blockers or magic quadrants, the matrix diagram is a simple square divided into four equal quadrants.

18 = 10 +8

17 = 10 +7

18 x 17 = 306

In the 2 x 2 array : 100+80+70+56 = 18 x 17 = 306

Therefore, In the 2 x 2 array, the sum of all squares is 18 x 17 = 306.

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The answer is x>−1/5 or x<1/5

3 0
3 years ago
HELP ME PLZZZ ASAP PLZZZ
AnnyKZ [126]
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The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of
kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

A=\frac{\sqrt{3} }{4} a^{2}

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}

A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}

A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}

Now, comparing areas:

\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )

\frac{A_{1}}{A_{2}} = 2.25

<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

7 0
3 years ago
Simplify -19 – 1 + (–24)
IrinaK [193]
First subtract -19 - 1 = -20

Next, + (-24) is the same as just simply subtracting 24

-20 - 24

Subtract that and you get -44
3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%20%3D%20ln%205" id="TexFormula1" title="e^{2x} = ln 5" alt="e^{2x} = ln 5" align=
KiRa [710]
e ^{2x} = ln5

Solve for the real domain

e ^{2x} = ln(5)

if f(x) =g(x), then ln(f(x))= ln(g(x))

ln(e ^{2x} ) = ln(ln(5))

Solve : <span>ln(e ^{2x} ) = ln(ln(5))
</span>
use the logarithmic definition :

ln(e^{f(x)} ) = f(x)

ln(e^{2x} ) = 2x

2x=ln(ln(5))

Divide both sides by 2 :

\frac{2x}{2} = \frac{ln(ln(5))}{2}

x= \frac{ln(ln(5))}{2}

hope this helps!

8 0
3 years ago
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