What numbers would be in the in the 4 sections of a 2 x 2 array that shows the problem 18 x 17?

Mathematics

1 answer:

kenny6666 [7]2 years ago

4 0

In the 2 x 2 array, the sum of all squares is 18 x 17 = 306.

The number in the 4 sections are 100, 80, 70, and 56.

A 2 x 2 array that shows the problem 18 x 17.

2 x 2 array has four blockers or magic quadrants, the matrix diagram is a simple square divided into four equal quadrants.

18 = 10 +8

17 = 10 +7

18 x 17 = 306

In the 2 x 2 array : 100+80+70+56 = 18 x 17 = 306

Therefore, In the 2 x 2 array, the sum of all squares is 18 x 17 = 306.

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A.Find the total and area of the compound figures

goldfiish [28.3K]

Answer:

(a) The total area of compound figure is $284.52ft^2$ .

(b) The total perimeter of compound figure is 68.84 ft.

Step-by-step explanation:

Perimeter: The total distance covered by the figure.

Area: It is defined as the space occupied by the figure.

Given:

Length of rectangular figure = 19 ft

Breadth of rectangular figure = 12 ft

Radius of circle, r = $\frac{12ft}{2} = 6 ft$

Part (a):

Now calculating the total area of the compound figure.

$\text{Total area}=\text{Area of rectangular figure}+\frac{1}{2}\times \text{Area of circle}\\\\\text{Total area}=\text{Length}\times \text{Breadth}+\frac{1}{2}\times \pi r^2$

Now putting all the given values in this formula, we get:

$\text{Total area}=(19ft\times 12ft)+\frac{1}{2}\times 3.14\times (6ft)^2\\\\\text{Total area}=284.52ft^2$

Part (b):

Now calculating the total perimeter of the compound figure.

$\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times \text{Circumference})\\\\\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)$

Now putting all the given values in this formula, we get:

$\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)\\\\\text{Total perimeter}=2\times 19ft+12ft+(\frac{1}{2}\times 2\times 3.14 \times 6ft)\\\\\text{Total perimeter}=68.84ft$