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Doss [256]
2 years ago
5

In a game, you have a 1/48 probability of winning $143 and a 47/48 probability of losing $10.

Mathematics
1 answer:
garik1379 [7]2 years ago
4 0

Answer:

<u>Losing $10</u>

Step-by-step explanation:

  • As the expected probability of losing $10 (47/48 = 97.9%) is much greater than the probability of winning $143 (1/48 = 2.1%), the expected winning is <u>losing $10</u>
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it rose to 5 degrees

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A sequence {an} is defined recursively, with a1 = 1, a2 = 2 and, for n &gt; 2, an =
Licemer1 [7]
I think you mean a_n= \frac{a_{n-1}}{a_{n-2}}
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ok

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ok, so notice a pattern
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I therefor conclude that a_n=a_{n+6w} where w is a whole number
and n>2ok, so
241=6*39+7
so therefor
a_{241}=a_{7+6(39)}
therefor the 241th term is same as a7 or 4

I say a241 is 4
7 0
4 years ago
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8 0
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