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Doss [256]
2 years ago
5

In a game, you have a 1/48 probability of winning $143 and a 47/48 probability of losing $10.

Mathematics
1 answer:
garik1379 [7]2 years ago
4 0

Answer:

<u>Losing $10</u>

Step-by-step explanation:

  • As the expected probability of losing $10 (47/48 = 97.9%) is much greater than the probability of winning $143 (1/48 = 2.1%), the expected winning is <u>losing $10</u>
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