Answer:
30th percentile:109
90th percentile: 188
Step-by-step explanation:
The given data set is:
129, 113, 200, 100, 105, 132, 100, 176, 146, 152
We arrange the data set in ascending order to obtain;
Array= ![100,100,105,113,129,132,146,176,200](https://tex.z-dn.net/?f=100%2C100%2C105%2C113%2C129%2C132%2C146%2C176%2C200)
The 30th percentile is located at
-th position, where n=10 is the number of items in the data set
This implies that the 30th percentile is at the 3rd position.
Since 3 is an integer, the 30th percentile is the average of the 3rd and 4th occurrence in the array;
This implies that the 30th percentile = ![\frac{105+113}{2}=\frac{218}{2}=109](https://tex.z-dn.net/?f=%5Cfrac%7B105%2B113%7D%7B2%7D%3D%5Cfrac%7B218%7D%7B2%7D%3D109)
The 90th percentile is located at
-th position, where n=10 is the number of items in the data set
This implies that the 90th percentile is at the 9th position.
Since 9 is an integer, the 90th percentile is the average of the 9th and 10th occurrence in the array;
This implies that the 90th percentile = ![\frac{176+200}{2}=\frac{376}{2}=188](https://tex.z-dn.net/?f=%5Cfrac%7B176%2B200%7D%7B2%7D%3D%5Cfrac%7B376%7D%7B2%7D%3D188)