We have to calculate the fraction of Paula`s allowance that she spent on other items if she already had spent 3/8 on clothes and 1/6 on entertainment. First we have to add: 3 / 8 + 1 / 6 = ( LCD is 24 ) = 9 / 24 + 4 / 24 = 13 / 24. Then : 1 - 13 / 24 = 24 / 24 - 13 / 24 = 11 / 24. Answer: She has spent 11 / 24<span> of her allowance on other items. </span>
Answer:
(224)10 = (E0)16
I dont know why it wouldnt be right this is the answer...Im acually confused now
Step-by-step explanation:
(224)10 = (E0)16
Step by step solution
Step 1: Divide (224)10 successively by 16 until the quotient is 0:
224/16 = 14, remainder is 0
14/16 = 0, remainder is 14
Step 2: Read from the bottom (MSB) to top (LSB) as E0. This is the hexadecimal equivalent of decimal number 224
Answer:
See the answers bellow
Step-by-step explanation:
For 51:
Using the definition of funcion, given f(x) we know that different x MUST give us different images. If we have two different values of x that arrive to the same f(x) this is not a function. So, the pair (-4, 1) will lead to something that is not a funcion as this would imply that the image of -4 is 1, it is, f(-4)=1 but as we see in the table f(-4)=2. So, as the same x, -4, gives us tw different images, this is not a function.
For 52:
Here we select the three equations that include a y value that are 1, 3 and 4. The other values do not have a y value, so if we operate we will have the value of x equal to a number but not in relation to y.
For 53:
As he will spend $10 dollars on shipping, so he has $110 for buying bulbs. As every bulb costs $20 and he cannot buy parts of a bulb (this is saying you that the domain is in integers) he will, at maximum, buy 5 bulbs at a cost of $100, with $10 resting. He can not buy 6 bulbs and with this $10 is impossible to buy 0.5 bulbs. So, the domain is in integers from 1 <= n <= 5. Option 4.
For 54:
As the u values are integers from 8 to 12, having only 5 possible values, the domain of the function will also have only five integers values, With this we can eliminate options 1 and 2 as they are in real numbers. Option C is the set of values for u but not the domain of c(u). Finally, we have that 4 is correct, those are the values you have if you replace the integer values from 8 to 12 in c(u). Option 4.
