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Gala2k [10]
3 years ago
11

I'm confused on simplifying radicals.​

Mathematics
2 answers:
Anton [14]3 years ago
5 0

Answer:

the answer is 4

Step-by-step explanation:

I use a calulator but if you dont have one then the way to do square roots is find a number say 4 and put it to the 2 power and it equaks 16 (4^2)=16. I cant really explain much more

lakkis [162]3 years ago
4 0

Answer: 4 or \sqrt{4 * 4}

To find the square root of a number, remember that there will be two factors that are the same that will give you the product.

Lets start from 1:

1 x 1 = 1

2 x 2 = 4

3 x 3 = 9

4 x 4 = 16

As you can see, 4 x 4 is 16. To make sure I'm correct, remember that a square roots consists two identical factors.

4 and 4 are the same numbers.

Therefore, \sqrt{16} = 4

It can also be written as \sqrt{4 * 4}

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If (x+2) is a factor of 3x^2-4kx-4k^2, then find the value(s) of k
IRINA_888 [86]

Answer:

The values of k will be:

k=-1,\:k=3

Step-by-step explanation:

Let the expression of polynomial P be

P\left(x\right)=3x^2-4kx-4k^2

Let the expression if the polynomial Q be

\:Q\left(x\right)=\:\left(x+2\right)\:

Plug in Q(x) = 0

0 = x+2

x = -2

As (x+2) is a factor of 3x²-4kx-4k²

substitute x = -2 in the the polynomial

3x²-4kx-4k² = 0

3\left(-2\right)^2-4k\left(-2\right)-4k^2\:=0

12+8k-4k^2=0

Write in the standard form ax²+bx+c = 0

-4k^2+8k+12=0

Factor out common term -4

-4\left(k^2-2k-3\right)=0

Factor k²-2k-3: (k+1)(k-3)

-4\left(k+1\right)\left(k-3\right)=0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

k+1=0\quad \mathrm{or}\quad \:k-3=0

solving k+1=0

k+1 = 0

k = -1

solving k-3=0

k-3=0

k = 3

Thus, the values of k will be:

k=-1,\:k=3

4 0
2 years ago
A football stadium holds 52,000 fans. A college student is doing research and determines that on any given game day, the home te
docker41 [41]
This problem is asking us to make an algebraic equation or representation of the situation. First we have to assign the variables which is already given in the problem. H is the number of the home team and V is the visiting team. Since the problem states there are the home team has five times as manyfans as the visiting team, then it can be represented as: 

H = 5V
Also, H + V = 52,000. H and V can then be solves by solving the 2 equations simultaneously. The results are 43,333 and 8,667. 
4 0
3 years ago
Graph each equation<br> Y=-2|-3X+3|+4<br><br> NEED HELP ASAP!!
HACTEHA [7]

Graph the absolute value by using the vertex and a few selected points

Point One: X= -1, Y= -8

Point Two: X= 0, Y= -2

Point Three: X= 1, Y= 4

Point Four: X= 2, Y= -2

Point Five: X= 3, Y= -8

The graph should look something like a mountain or an upside down V

3 0
3 years ago
In the diagram below AFB is congruent to EFD if EFD = 5x + 6, DFC = 19x - 15, and EFC = 17x + 19, find AFE
yanalaym [24]

The angle m∠AFE is 128 degrees.

<h3>How to find angles?</h3>

∠AFB ≅ ∠EFD

∠EFD = 5x + 6

m∠DFC = (19x - 15)°

m∠EFC = (17x + 19)°

m∠AFE = ?

m∠AFB + m ∠EFD + m∠AFE = 180

Therefore,

5x + 6 + 5x + 6 + m∠AFE = 180

5x + 5x + 6 + 6 + m∠AFE = 180

10x + 12 + m∠AFE = 180

10x + m∠AFE = 180 - 12

10x + m∠AFE  = 168

m∠AFE = 168 - 10x

m∠EFC =  m ∠EFD + m∠DFC

17x + 19 = 5x + 6 + 19x - 15

17x - 5x - 19x = 6 - 15 - 19

-7x = - 28

x = 28 / 7

x = 4

Therefore,

m∠AFE = 168 - 10x

m∠AFE = 168 - 10(4)

m∠AFE = 168 - 40

m∠AFE = 128°

Therefore, the angle m∠AFE = 128°

learn more on angles here: brainly.com/question/13212279

#SPJ1

7 0
2 years ago
Assume a warehouse operates 24 hours a day. Truck arrivals follow Poisson distribution with a mean rate of 36 per day and servic
kirill [66]

The expected waiting time in system for typical truck is 2 hours.

Step-by-step explanation:

Data Given are as follows.

Truck arrival rate is given by,   α  = 36 / day

Truck operation departure rate is given,   β= 48 / day

A constructed queuing model is such that so that queue lengths and waiting time can be predicted.

In queuing theory, we have to achieve economic balance between number of customers arriving into system and that of leaving the system whether referring to people or things, in correlating such variables as how customers arrive, how service meets their requirements, average service time and extent of variations, and idle time.

This problem is solved by using concept of Single Channel Arrival with exponential service infinite populate model.

Waiting time in system is given by,

w_{s} = \frac{1}{\alpha - \beta  }

        where w_s is waiting time in system

                   \alpha is arrival rate described Poission distribution

                   \beta is service rate described by Exponential distribution

w_{s} = \frac{1}{\alpha - \beta  }

w_{s} = \frac{1}{48 - 36 }

w_{s} = \frac{1}{12 } day

w_{s} = \frac{1}{12 }  \times 24  hour        ...it is due to 1 day = 24 hours

w_{s} = 2 hours

Therefore, time required for waiting in system is 2 hours.

           

                   

5 0
3 years ago
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