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garri49 [273]
3 years ago
8

Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi

t. x2 - 4x + y2 + 8y = -4
Mathematics
2 answers:
solong [7]3 years ago
8 0

The center-radius form of the circle equation is in the format (x – h)^2 + (y – k)^2 = r^2, with the center being at the point (h, k) and the radius being "r". We do as follows:


x^2 − 4x + y^2 + 8y = −4

(x^2 − 4x) + (y^2 + 8y) = −4

(x^2 − 4x + 4) + (y^2 + 8y + 16) = −4 +4 + 16

(x - 2)^2 + ( y + 4)^2 = 16 = 4^2


Center: (-2 , 4 )

radius: 4

Vikki [24]3 years ago
7 0
The equation of the circle: (x-a)^2+(y-b)^2=r^2

where:
(a; b) - coordinates of the center
r - a radius

Use: (a\pm b)^2=a^2\pm2ab+b^2\ \ \ \ (*)

We have:

x^2-4x+y^2+8y=-4\\\\x^2-2x\cdot2+y^2+2y\cdot4=-4\ \ \ |add\ 2^2\ and\ 4^2\ to\ both\ sides\\\\\underbrace{x^2-2x\cdot2+2^2}_{(*)}+\underbrace{y^2+2y\cdot4+4^2}_{(*)}=-4+2^2+4^2\\\\(x-2)^2+(y+4)^2=-4+4+16\\\\(x+2)^2+(y-4)^2=16\\\\(x+2)^2+(y-4)^2=4^2

Answer:
The center: (-2; 4)
The radius: r = 4
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Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How m
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Value of the given statement:

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<h3>What is Probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

According to the given information:

1) There are a total of 10 slips after adding.

8 slip with 3 on it

2 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 11)  x 3 + (2/ 11)  x 9

24 / 11 + 24 / 11 = 4.36

2 )No of total slips after addition = 12

8 slip with 3 on it

4 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 12)  x 3 + (4 / 12)  x 9

2 + 3 = 5

3 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 6

24 + 18 + 9n / 10 + n  = 6

42 + 9n = 60 + 6n

3 n = 18

n = 6

4 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

expectation value = probability of 3 x 3 + probability of 9 x 9

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 8

24 + 18 + 9n / 10 + n  = 8

42 + 9n = 80 + 8n

n = 38

Minimum of 38 has to be added .

To know more about Probability visit:

brainly.com/question/17487084

#SPJ4

I understand that the question you are looking for is:

1:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add one additional $9$ to the bag? 2:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add two additional $9$'s (instead of just one) to the bag? 3:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do we have to add to make the expected value equal to $6$? 4:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do I have to add before the expected value is at least $8$?

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X + 5y = 28<br> - x - 2y = -13
bazaltina [42]

Answer:

x=3

y=5

Step-by-step explanation:

x+5y=28 (i)

-x-2y=-13. (ii)

add equation 2 from equation 1

x+5y=28

-x-2y=-13

3y=15

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put the value of y in equation 1

x+5y=28

x+5*5=28

x+25=28

x=28-25

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