2 years ago

Complete the table y=2x²-2 x = 0,1,-1,2,-2 y= ?

Mathematics

1 answer:

Tasya [4]2 years ago

8 0

Step-by-step explanation:

X- axis interception points of 2x² - 2, x = 0: None

y- axis interception point of 2x²-2, x=0:

Y Intercepts: (0, - 2)

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What is the lim of (((1/x)-(1/2))/x-2) , as x approaches 2

Katyanochek1 [597]

I assume the denominator is $x-2$ .

$\lim_{x\to2}\dfrac{\dfrac{1}{x}-\dfrac{1}{2}}{x-2}=\\
\lim_{x\to2}\dfrac{\dfrac{2}{2x}-\dfrac{x}{2x}}{x-2}=\\
\lim_{x\to2}\dfrac{\dfrac{2-x}{2x}}{x-2}=\\
\lim_{x\to2}\dfrac{2-x}{2x(x-2)}}=\\
\lim_{x\to2}-\dfrac{x-2}{2x(x-2)}}=\\
\lim_{x\to2}-\dfrac{1}{2x}}=\\
-\dfrac{1}{2\cdot2}=\\
-\dfrac{1}{4}=
$